In boolean algebra, if `A=1` and `B=0` then the value of `A+barB` is

Options

A. A
B. A.B
C. A+B
D. Both (a) and (c )

Explanation

To solve the question, we need to evaluate the expression \( A + \overline{B} \) given that \( A = 1 \) and \( B = 0 \).

### Step-by-step Solution:

1. **Identify the values of A and B**:
- We are given \( A = 1 \) and \( B = 0 \).

2. **Calculate \( \overline{B} \)**:
- The bar over B (denoted as \( \overline{B} \)) represents the NOT operation in Boolean algebra.
- Since \( B = 0 \), we have:
\[ \overline{B} = 1 \]
- This is because the NOT operation flips the value: \( \overline{0} = 1 \).

3. **Substitute the values into the expression**:
- Now we substitute \( A \) and \( \overline{B} \) into the expression \( A + \overline{B} \):
\[ A + \overline{B} = 1 + 1 \]

4. **Evaluate the expression**:
- In Boolean algebra, the OR operation (denoted by +) states that if at least one of the operands is 1, the result is 1. Therefore:
\[ 1 + 1 = 1 \]

5. **Final Result**:
- Thus, the value of \( A + \overline{B} \) is:
\[ 1 \]

### Conclusion:
The final answer is \( 1 \).