The number of electrons that must be removed from an electrically neutral silver dollar to give it a charge of +2.4C is

Options

A. `2.5xx10^(19)`
B. `1.5xx10^(19)`
C. `1.5xx10^(-19)`
D. `2.5xx10^(-19)`

Explanation

To determine the number of electrons that must be removed from an electrically neutral silver dollar to give it a charge of +2.4 C, we can follow these steps:

### Step 1: Understand the Charge of an Electron
The charge of a single electron is approximately \( -1.6 \times 10^{-19} \) coulombs. When electrons are removed from an object, it becomes positively charged.

### Step 2: Set Up the Equation
If \( n \) is the number of electrons removed, the total positive charge \( Q \) gained by the silver dollar can be expressed as:
\[ Q = n \times e \]
where \( e \) is the charge of one electron.

### Step 3: Substitute the Known Values
We want the silver dollar to have a charge of \( +2.4 \) C. Therefore, we can write:
\[ 2.4 = n \times (1.6 \times 10^{-19}) \]

### Step 4: Solve for \( n \)
Rearranging the equation to solve for \( n \):
\[ n = \frac{2.4}{1.6 \times 10^{-19}} \]

### Step 5: Calculate \( n \)
Now, performing the division:
\[ n = \frac{2.4}{1.6} \times 10^{19} \]
Calculating \( \frac{2.4}{1.6} \):
\[ \frac{2.4}{1.6} = 1.5 \]
Thus,
\[ n = 1.5 \times 10^{19} \]

### Conclusion
The number of electrons that must be removed from the silver dollar to give it a charge of +2.4 C is \( 1.5 \times 10^{19} \).

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