Home
Class 12
PHYSICS
Assertion : Total flux through a closed ...

Assertion : Total flux through a closed surface is zero if no charge is enclosed by the surface.
Reason : Gauss law is true for any closed surface, no matter what its shape or size is.

A

If both assertion and reason are true and reason is the correct explanation of assertion.

B

If both assertion and reason are true but reason is not the correct explanation of assertion.

C

If assertion is true but reason is false.

D

If both assertion and reason are false.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the given question, we need to analyze both the assertion and the reason provided. ### Step 1: Understanding the Assertion The assertion states that "Total flux through a closed surface is zero if no charge is enclosed by the surface." According to Gauss's law, the electric flux (Φ) through a closed surface is given by the equation: \[ \Phi = \frac{Q_{\text{enc}}}{\epsilon_0} \] where \(Q_{\text{enc}}\) is the total charge enclosed by the surface and \(\epsilon_0\) is the permittivity of free space. If there is no charge enclosed (\(Q_{\text{enc}} = 0\)), then: \[ \Phi = \frac{0}{\epsilon_0} = 0 \] Thus, the assertion is true. ### Step 2: Understanding the Reason The reason states that "Gauss law is true for any closed surface, no matter what its shape or size is." Gauss's law applies universally to all closed surfaces, regardless of their geometry. This means that the law holds true for spherical, cylindrical, or any arbitrary closed surfaces. Therefore, this statement is also true. ### Step 3: Analyzing the Relationship While both the assertion and the reason are true, we need to determine if the reason correctly explains the assertion. The assertion is specifically about the condition of having no charge enclosed leading to zero flux, while the reason discusses the general applicability of Gauss's law. Therefore, the reason does not directly explain why the total flux is zero when no charge is enclosed. ### Conclusion Both the assertion and the reason are true, but the reason is not a correct explanation for the assertion. Thus, the correct answer is that both statements are true, but the reason is not a correct explanation for the assertion. ### Final Answer - Assertion: True - Reason: True, but not a correct explanation for the assertion.
To solve the given question, we need to analyze both the assertion and the reason provided. ### Step 1: Understanding the Assertion The assertion states that "Total flux through a closed surface is zero if no charge is enclosed by the surface." According to Gauss's law, the electric flux (Φ) through a closed surface is given by the equation: \[ \Phi = \frac{Q_{\text{enc}}}{\epsilon_0} \] where \(Q_{\text{enc}}\) is the total charge enclosed by the surface and \(\epsilon_0\) is the permittivity of free space. If there is no charge enclosed (\(Q_{\text{enc}} = 0\)), then: ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ELECTRIC CHARGES AND FIELDS

    NCERT FINGERTIPS ENGLISH|Exercise Electric Charges|5 Videos

  • ELECTRIC CHARGES AND FIELDS

    NCERT FINGERTIPS ENGLISH|Exercise Charging By Induction|3 Videos

  • ELECTRIC CHARGES AND FIELDS

    NCERT FINGERTIPS ENGLISH|Exercise Assertion And Reason|15 Videos

  • DUAL NATURE OF RADIATION AND MATTER

    NCERT FINGERTIPS ENGLISH|Exercise Assertion And Reason|15 Videos

  • ELECTROMAGNETIC INDUCTION

    NCERT FINGERTIPS ENGLISH|Exercise NCERT Exemplar|6 Videos

Similar Questions

Explore conceptually related problems

The net flux passing through a closed surface enclosing unit charge is

If a charge is enclosed by the surface of the sphere then total flux emitted from the surface will be:

Knowledge Check

  • The net magnetic flux through any closed surface, kept in a magnetic field is

    A
    zero
    B
    `(mu_(0))/(4pi)`
    C
    `4pimu_(0)`
    D
    `(4mu_(0))/(pi)`

    • Similar Questions

    Explore conceptually related problems

    The net magnetic flux through any closed surface, kept in a magnetic field is

    If the flux of the electric field through a closed surface is zero,

    A closed surface encloses a net charge of -3.60 muC . What is the net electric flux through the surface? (b) The electric flux through a closed surface is found to be 780 N-m^2//C . What quantity of charge is enclosed by the surface? (c) The closed surface in part (b) is a cube with sides of length 2.50 cm. From the information given in part (b), is it possible to tell where within the cube the charge is located? Explain.

    (a) define electrie flux. Write its, S.I unit. " Gauses's law in electrostatis is true for any closed surface, no matter what its shape or size is. Justify this statement with the help of a suitable example. (b) Use Gauss's law to prove that the electric field inside a uniformly charged spherical shell is zero.

    Flux (in S.I. units) coming out and eantering a closed surface is shown in the figure. Find charge enclosed by the closed surface.

    If the number of electric lines of force emerging out of a closed surfsace is 1000, then the charge enclosed by the surface is

    This question contains Statement -1 and Stantement -2 Of the four choices given after the statements, choose the one that best desctibes the two statemesnts. Statement -1: For a mass M kept at the center of a cube of side 'a', the flux of gravitational field passing through its sides 4piGM. Statement -2: If the direction of a field due to a point source is radial and its dependence on the distance 'r' from the source is given as (1)/(r^2) , its flux through a closed surface depends only on the strength of the source enclosed by the surface and not on the size or shape of the surface.

    Home
    Profile