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A spherical capacitor consists of two co...

A spherical capacitor consists of two concentric spherical shells of outer radius r1 and inner radius r2, held in position by suitable insulating supports. calculate the capacitance of this spherical capacitor.

A

`(4piepsi_(0)r_(1)r_(2))/(r_(1)-r_(2))`

B

`(4piepsi_(0)-(r_(2)-r_(1)))/(r_(1)r_(2))`

C

`(r_(1)r_(2))/(4 pi epsi_(0)(r_(2)-r_(1)))`

D

`((r_(1)-r_(2)))/(4 pi epsi_(0)r_(1)r_(2))`

Text Solution

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The correct Answer is:
To calculate the capacitance of a spherical capacitor consisting of two concentric spherical shells with outer radius \( r_1 \) and inner radius \( r_2 \), we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Setup**: - We have two concentric spherical shells: the inner shell (radius \( r_2 \)) and the outer shell (radius \( r_1 \)). - The inner shell is given a positive charge \( +Q \), which distributes uniformly over its surface. 2. **Induction Effect**: - The positive charge on the inner shell induces a negative charge \( -Q \) on the inner surface of the outer shell (radius \( r_1 \)). - Consequently, the outer surface of the outer shell will have a charge of \( +Q \) (since the outer shell is grounded, it will lose some positive charge to the ground). 3. **Electric Field Calculation**: - The electric field \( E \) in the region between the two shells (from \( r_2 \) to \( r_1 \)) can be calculated using Gauss's law. The electric field due to a uniformly charged sphere at a distance \( r \) (where \( r_2 < r < r_1 \)) is given by: \[ E = \frac{1}{4\pi \epsilon_0} \cdot \frac{Q}{r^2} \] 4. **Potential Difference Calculation**: - The potential difference \( V \) between the inner shell (at \( r_2 \)) and the outer shell (at \( r_1 \)) is given by: \[ V = V_A - V_B = -\int_{r_2}^{r_1} E \, dr \] - Substituting the expression for \( E \): \[ V = -\int_{r_2}^{r_1} \frac{1}{4\pi \epsilon_0} \cdot \frac{Q}{r^2} \, dr \] - Evaluating the integral: \[ V = -\frac{Q}{4\pi \epsilon_0} \left[-\frac{1}{r}\right]_{r_2}^{r_1} = \frac{Q}{4\pi \epsilon_0} \left(\frac{1}{r_2} - \frac{1}{r_1}\right) \] 5. **Capacitance Calculation**: - The capacitance \( C \) of the spherical capacitor is defined as: \[ C = \frac{Q}{V} \] - Substituting the expression for \( V \): \[ C = \frac{Q}{\frac{Q}{4\pi \epsilon_0} \left(\frac{1}{r_2} - \frac{1}{r_1}\right)} = \frac{4\pi \epsilon_0}{\left(\frac{1}{r_2} - \frac{1}{r_1}\right)} \] - Simplifying further: \[ C = \frac{4\pi \epsilon_0 r_1 r_2}{r_1 - r_2} \] ### Final Result: The capacitance of the spherical capacitor is given by: \[ C = \frac{4\pi \epsilon_0 r_1 r_2}{r_1 - r_2} \]

To calculate the capacitance of a spherical capacitor consisting of two concentric spherical shells with outer radius \( r_1 \) and inner radius \( r_2 \), we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Setup**: - We have two concentric spherical shells: the inner shell (radius \( r_2 \)) and the outer shell (radius \( r_1 \)). - The inner shell is given a positive charge \( +Q \), which distributes uniformly over its surface. ...
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