An 8 cm long wire carrying a current of 10 A is placed inside a solenoid perpendicular to its axis. If the magnetic field inside the solenoid is 0.3 T, then magnetic force on the wire is

Options

A. 0.14N
B. 0.24N
C. 0.34N
D. 0.44N

Explanation

To solve the problem of finding the magnetic force on a wire placed inside a solenoid, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Length of the wire (L) = 8 cm = 0.08 m (convert to meters)
- Current (I) = 10 A
- Magnetic field (B) = 0.3 T
- Angle (θ) = 90° (since the wire is perpendicular to the magnetic field)

2. **Use the Formula for Magnetic Force:**
The magnetic force (F) on a current-carrying wire in a magnetic field is given by the formula:
\[ F = BIL \sin \theta \]

3. **Substitute the Values into the Formula:**
- Substitute B = 0.3 T, I = 10 A, L = 0.08 m, and θ = 90° (where \(\sin 90° = 1\)):
\[ F = 0.3 \times 10 \times 0.08 \times \sin(90°) \]
\[ F = 0.3 \times 10 \times 0.08 \times 1 \]

4. **Calculate the Force:**
- Perform the multiplication:
\[ F = 0.3 \times 10 = 3 \]
\[ F = 3 \times 0.08 = 0.24 \text{ N} \]

5. **Final Answer:**
The magnetic force on the wire is:
\[ F = 0.24 \text{ N} \]