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A charged particle is moving in a cyclot...

A charged particle is moving in a cyclotron, what effect on the radius of path of this charged particle will occur when the frequency of the radio frequency field is doubled?

A

It will also be doubled.

B

It will be halved.

C

It will be increased by four times.

D

It will remain unchanged.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the relationship between the radius of the path of a charged particle in a cyclotron and the frequency of the radio frequency field. ### Step-by-Step Solution: 1. **Understanding the Cyclotron Motion**: - A charged particle moving in a magnetic field experiences a centripetal force that keeps it in circular motion. This force is provided by the magnetic force acting on the charged particle. 2. **Equating Forces**: - The centripetal force acting on the particle can be expressed as: \[ F_c = \frac{mv^2}{r} \] - The magnetic force acting on the charged particle is given by: \[ F_m = qvB \] - Setting these two forces equal gives: \[ \frac{mv^2}{r} = qvB \] 3. **Solving for Radius (R)**: - Rearranging the equation to solve for the radius \( r \): \[ r = \frac{mv}{qB} \] - This equation shows that the radius \( r \) depends on the mass \( m \), velocity \( v \), charge \( q \), and magnetic field \( B \). 4. **Understanding Frequency**: - The frequency \( f \) of the charged particle's motion in the cyclotron can be derived from the time period \( T \): \[ T = \frac{2\pi m}{qB} \] - The frequency is the reciprocal of the time period: \[ f = \frac{1}{T} = \frac{qB}{2\pi m} \] 5. **Effect of Doubling Frequency**: - If the frequency \( f \) is doubled, it implies: \[ f' = 2f = \frac{qB'}{2\pi m} \] - This means that the magnetic field \( B \) must also change in order to maintain the relationship, but the radius \( r \) does not depend on frequency directly. 6. **Conclusion**: - Since the radius \( r \) is independent of the frequency \( f \), doubling the frequency of the radio frequency field does not change the radius of the path of the charged particle in the cyclotron. Therefore, the radius remains unchanged. ### Final Answer: The radius of the path of the charged particle will remain unchanged when the frequency of the radio frequency field is doubled. ---

To solve the problem, we need to analyze the relationship between the radius of the path of a charged particle in a cyclotron and the frequency of the radio frequency field. ### Step-by-Step Solution: 1. **Understanding the Cyclotron Motion**: - A charged particle moving in a magnetic field experiences a centripetal force that keeps it in circular motion. This force is provided by the magnetic force acting on the charged particle. 2. **Equating Forces**: ...
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