Home
Class 12
PHYSICS
As a result of change in the magnetic fl...

As a result of change in the magnetic flux linked to the closed loop shown in the fig, an e.m.f. V volt is induced in the loop. The work done (joule) in taking a charge Q coulomb once along the loop is

A

qV

B

zero

C

2qV

D

`(qV)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • ELECTROMAGNETIC INDUCTION

    NCERT FINGERTIPS ENGLISH|Exercise Lenz'S Law And Conservation Of Energy|13 Videos
  • ELECTROMAGNETIC INDUCTION

    NCERT FINGERTIPS ENGLISH|Exercise Motional Electromotive Force|15 Videos
  • ELECTROMAGNETIC INDUCTION

    NCERT FINGERTIPS ENGLISH|Exercise Magnetic Flux|3 Videos
  • ELECTRIC CHARGES AND FIELDS

    NCERT FINGERTIPS ENGLISH|Exercise Assertion And Reason|15 Videos
  • ELECTROMAGNETIC WAVES

    NCERT FINGERTIPS ENGLISH|Exercise Assertion And Reason|15 Videos

Similar Questions

Explore conceptually related problems

At time t=0 magnetic Field of 1000 Gausses is passing perpendicularly through the area defined by the closed loop shown in the Figure. If the magnetic Field reduces linearly to 500 Gausses, in the next 5s, then induces EMF in the loop is:

Magnetic flux (in Wb) linked with a closed loop varies with time (in S) as Φ =2t^2+1. The magnitude of induced emf at t=1 s is

Magnetic flux (in Wb) linked with a closed loop varies with time (in S) as Φ =2t^2+1. The magnitude of induced emf at t=1 s is

A square loop of side 1 m is placed in a perpendicular magnetic field. Half of the area of the loop lies inside the magnetic field . A battery of emf 10 V and negligible intermal resistance is connected in the loop . The magnetic field changes with time according to the relation B= (0.01 -2t) tesla . The resultant emf of the circuit is

A long solenoid having n = 200 turns per metre has a circular cross-section of radius a_(1) = 1 cm . A circular conducting loop of radius a_(2) = 4 cm and resistance R = 5 (Omega) encircles the solenoid such that the centre of circular loop coincides with the midpoint of the axial line of the solenoid and they have the same axis as shown in Fig. A current 't' in the solenoid results in magnetic field along its axis with magnitude B = (mu)ni at points well inside the solenoid on its axis. We can neglect the insignificant field outside the solenoid. This results in a magnetic flux (phi)_(B) through the circular loop. If the current in the winding of solenoid is changed, it will also change the magnetic field B = (mu)_(0)ni and hence also the magnetic flux through the circular loop. Obvisouly, it will result in an induced emf or induced electric field in the circular loop and an induced current will appear in the loop. Let current in the winding of solenoid be reduced at a rate of 75 A //sec . Magentic flux through the loop due to external magnetic field will be I is the current in the loop a_(1) is the radius of solendoid and a_(1)=1cm (given) a_(2) is the radius of circular loop and a_(2)=4cm (given) i is hte current in the solenoid

A long solenoid having n = 200 turns per metre has a circular cross-section of radius a_(1) = 1 cm . A circular conducting loop of radius a_(2) = 4 cm and resistance R = 5 (Omega) encircles the solenoid such that the centre of circular loop coincides with the midpoint of the axial line of the solenoid and they have the same axis as shown in Fig. A current 't' in the solenoid results in magnetic field along its axis with magnitude B = (mu)ni at points well inside the solenoid on its axis. We can neglect the insignificant field outside the solenoid. This results in a magnetic flux (phi)_(B) through the circular loop. If the current in the winding of solenoid is changed, it will also change the magnetic field B = (mu)_(0)ni and hence also the magnetic flux through the circular loop. Obvisouly, it will result in an induced emf or induced electric field in the circular loop and an induced current will appear in the loop. Let current in the winding of solenoid be reduced at a rate of 75 A //sec . When the current in the solenoid becomes zero so that external magnetic field for the loop stops changing, current in the loop will follow a differenctial equation given by [You may use an approximation that field at all points in the area of loop is the same as at the centre

A metallic square loop ABCD is moving in its own plane with velocity v in a uniform magnetic field perpendicular to its plane as shown in the figure, Find a) in which sides of the loop electric field is induced. b) Net emf induced in the loop. c) If one side .BC. is outside the field with remaining loop in the field and is being pulled on D with a constant velocity then induced current in the loop.

A conducting rod of length l slides at constant velocity v on two parallel conducting rails, placed in a uniform and constant magnetic field B perpendicular to the plane of the rails as shown in Fig.3.49. A resistance R is connected between the two ends of the rails. (a) Idenify the cause which produces change in magnetic flux. (b) Identify the direction of current in the loop. ( c) Determine the emf induced in the loop. (d) Compute the electric power dissipated in the resistor. (e) Calcualte the mechenical power required to pull the rod at a cinstant velovity.

A square loop of side b is rotated in a constant magnetic field B at angular frequency omega as shown in the figure. What is the emf induced in it?

Current in a long current carrying wire is I=2t A conducting loop is placed to the right of this wire. Find a. magnetic flux phi_B passing through the loop. b. induced emf|e| prodced in the loop. c. if total resistance of the loop is R , then find induced current I_("in") in the loop.

NCERT FINGERTIPS ENGLISH-ELECTROMAGNETIC INDUCTION-Faraday'S Law Of Induction
  1. Faraday's law are consequence of conservation of

    Text Solution

    |

  2. Two circular, similar, coaxial loops carry equal currents in the same...

    Text Solution

    |

  3. As a result of change in the magnetic flux linked to the closed loop s...

    Text Solution

    |

  4. A coil of area 0.4m^(2) has 100 turns. A magnetic field of 0.04 Wb m^(...

    Text Solution

    |

  5. A coil of area 500cm^(2) and having 1000 turns is held perpendicular t...

    Text Solution

    |

  6. A long solenoid with 10 turns per cm has a small loop of area 3cm^(2) ...

    Text Solution

    |

  7. An air cored solenoid with length 20 cm area of cross section 20cm2. T...

    Text Solution

    |

  8. The magnetic flux through a coil perpendicluar to its plane and direct...

    Text Solution

    |

  9. A long solenoid 'S' has 'n' turns per meter, with diameter 'a'. At the...

    Text Solution

    |

  10. A conducting circular loop is placed in a uniform magnetic field, B=0....

    Text Solution

    |

  11. A circular coil of radius 8cm, 400 turns and resistance 2Omega is plac...

    Text Solution

    |

  12. A square loop of side 12 cm and resistance 0.6Omega is placed vertical...

    Text Solution

    |

  13. A rectangular coil of 100 turns and size 0.1mxx0.05m is placed perpend...

    Text Solution

    |

  14. A unifrom magnetic field B points vertically up and is slowly changed ...

    Text Solution

    |

  15. A magnetic field B is confined to a region r le a and points out of th...

    Text Solution

    |

  16. A metal ring is held horizontally and bar magnet is dropped through th...

    Text Solution

    |