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Two coils have self-inductance L(1) = 4m...

Two coils have self-inductance `L_(1) = 4mH` and `L_(2) = 1 mH` respectively. The currents in the two coils are increased at the same rate. At a certain instant of time both coils are given the same power. If `I_(1)` and `I_(2)` are the currents in the two coils, at that instant of time respectively, then the value of `(I_(1)//I_(2))` is :

A

`(1)/(8)`

B

`(1)/(4)`

C

`(1)/(2)`

D

1

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To solve the problem, we need to find the ratio of the currents \( I_1 \) and \( I_2 \) in two coils with given self-inductances, under the condition that they are supplied with the same power. Let's go through the solution step by step. ### Step 1: Write the expressions for the induced EMF The induced EMF (voltage) across each coil can be expressed using the formula for self-inductance: \[ V_1 = L_1 \frac{dI_1}{dt} \] \[ V_2 = L_2 \frac{dI_2}{dt} \] where \( L_1 = 4 \, \text{mH} \) and \( L_2 = 1 \, \text{mH} \). ### Step 2: Write the power equations The power \( P \) in each coil can be expressed as: \[ P_1 = V_1 I_1 \] \[ P_2 = V_2 I_2 \] Since both coils are given the same power at a certain instant, we can equate the two power expressions: \[ V_1 I_1 = V_2 I_2 \] ### Step 3: Substitute the expressions for voltage Substituting the expressions for \( V_1 \) and \( V_2 \) into the power equation gives: \[ (L_1 \frac{dI_1}{dt}) I_1 = (L_2 \frac{dI_2}{dt}) I_2 \] ### Step 4: Substitute the values of self-inductance Substituting \( L_1 = 4 \, \text{mH} \) and \( L_2 = 1 \, \text{mH} \): \[ (4 \times 10^{-3} \frac{dI_1}{dt}) I_1 = (1 \times 10^{-3} \frac{dI_2}{dt}) I_2 \] ### Step 5: Simplify the equation This simplifies to: \[ 4 I_1 \frac{dI_1}{dt} = I_2 \frac{dI_2}{dt} \] ### Step 6: Use the condition of equal rates of change of current Since the currents in both coils are increased at the same rate, we have: \[ \frac{dI_1}{dt} = \frac{dI_2}{dt} \] Thus, we can cancel \( \frac{dI_1}{dt} \) and \( \frac{dI_2}{dt} \) from both sides: \[ 4 I_1 = I_2 \] ### Step 7: Find the ratio of the currents Rearranging gives: \[ \frac{I_1}{I_2} = \frac{1}{4} \] ### Conclusion Thus, the value of \( \frac{I_1}{I_2} \) is: \[ \frac{I_1}{I_2} = \frac{1}{4} \]

To solve the problem, we need to find the ratio of the currents \( I_1 \) and \( I_2 \) in two coils with given self-inductances, under the condition that they are supplied with the same power. Let's go through the solution step by step. ### Step 1: Write the expressions for the induced EMF The induced EMF (voltage) across each coil can be expressed using the formula for self-inductance: \[ V_1 = L_1 \frac{dI_1}{dt} \] \[ ...
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