A fax message is to be sent from Delhi to Washington via a geostationary satellite. The minimum distance between the dispatch and its getting received is (Take height of the geostationary satellite=36000km)

Options

A. `72xx10^(3)km`
B. `12xx10^(3)km`
C. `27xx10^(3)km`
D. `18xx10^(3)km`

Explanation

To solve the problem of finding the minimum distance for a fax message sent from Delhi to Washington via a geostationary satellite, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Height of the Satellite**:
- The height of the geostationary satellite is given as 36,000 km.

2. **Determine the Path of the Signal**:
- The signal travels from the ground station in Delhi to the satellite and then from the satellite to the ground station in Washington. This means the signal travels up to the satellite and then back down.

3. **Calculate the Total Distance**:
- Since the signal travels to the satellite and back down, the total distance (D) can be calculated as:
\[ D = 2 \times \text{height of the satellite} \]
- Substituting the height:
\[ D = 2 \times 36,000 \text{ km} = 72,000 \text{ km} \]

4. **Express the Distance in Scientific Notation**:
- The distance can also be expressed in scientific notation:
\[ D = 72,000 \text{ km} = 7.2 \times 10^4 \text{ km} \]

5. **Conclusion**:
- Therefore, the minimum distance between the dispatch and its receiving point is 72,000 km.

### Final Answer:
The minimum distance is **72,000 km** or **7.2 x 10^4 km**.

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