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The output current of an 80% mondulating...

The output current of an 80% mondulating amplitude modulated generator is 1.8A. To what value will the current rise if the generator is additionally modulated by another audiowave of modulation index 0.6?

A

1.71A

B

1.81A

C

1.91A

D

2.01A

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The correct Answer is:
To solve the problem step by step, we will use the given information and the relevant formulas for amplitude modulation. ### Step 1: Identify the given values - The output current \( I_T \) of the generator is given as \( 1.8 \, A \). - The modulation index for the first modulation \( \mu_1 \) is \( 80\% \) which can be converted to a decimal as \( \mu_1 = 0.8 \). - The modulation index for the second modulation \( \mu_2 \) is \( 0.6 \). ### Step 2: Use the formula to find the carrier current \( I_C \) The formula relating the total current \( I_T \) to the carrier current \( I_C \) and the modulation index \( \mu_1 \) is given by: \[ I_T = I_C \sqrt{1 + \frac{\mu_1^2}{2}} \] Rearranging this formula to find \( I_C \): \[ I_C = \frac{I_T}{\sqrt{1 + \frac{\mu_1^2}{2}}} \] ### Step 3: Substitute the values to calculate \( I_C \) Substituting the known values into the equation: \[ I_C = \frac{1.8}{\sqrt{1 + \frac{(0.8)^2}{2}}} \] Calculating \( \frac{(0.8)^2}{2} \): \[ \frac{(0.8)^2}{2} = \frac{0.64}{2} = 0.32 \] Now substituting this back into the equation for \( I_C \): \[ I_C = \frac{1.8}{\sqrt{1 + 0.32}} = \frac{1.8}{\sqrt{1.32}} \] ### Step 4: Calculate \( \sqrt{1.32} \) Calculating \( \sqrt{1.32} \): \[ \sqrt{1.32} \approx 1.1487 \] Now substituting this value back to find \( I_C \): \[ I_C \approx \frac{1.8}{1.1487} \approx 1.568 \] ### Step 5: Calculate the new total current \( I_{net} \) The new total current \( I_{net} \) when modulated by the second audio wave can be calculated using the formula: \[ I_{net} = I_C \sqrt{1 + \frac{\mu_1^2}{2} + \frac{\mu_2^2}{2}} \] Substituting the values we have: \[ I_{net} = I_C \sqrt{1 + \frac{(0.8)^2}{2} + \frac{(0.6)^2}{2}} \] Calculating \( \frac{(0.6)^2}{2} \): \[ \frac{(0.6)^2}{2} = \frac{0.36}{2} = 0.18 \] Now substituting this into the equation: \[ I_{net} = I_C \sqrt{1 + 0.32 + 0.18} = I_C \sqrt{1.5} \] ### Step 6: Calculate \( \sqrt{1.5} \) Calculating \( \sqrt{1.5} \): \[ \sqrt{1.5} \approx 1.2247 \] Now substituting \( I_C \) back into the equation for \( I_{net} \): \[ I_{net} \approx 1.568 \times 1.2247 \approx 1.92 \] ### Final Answer The new total current \( I_{net} \) will rise to approximately \( 1.92 \, A \). ---

To solve the problem step by step, we will use the given information and the relevant formulas for amplitude modulation. ### Step 1: Identify the given values - The output current \( I_T \) of the generator is given as \( 1.8 \, A \). - The modulation index for the first modulation \( \mu_1 \) is \( 80\% \) which can be converted to a decimal as \( \mu_1 = 0.8 \). - The modulation index for the second modulation \( \mu_2 \) is \( 0.6 \). ### Step 2: Use the formula to find the carrier current \( I_C \) ...
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