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When 1.04 g of BaCl2 is present in 10^5 ...

When 1.04 g of `BaCl_2` is present in `10^5` g of solution the concentration of solution is

A

0.104 ppm

B

10.4 ppm

C

0.0104 ppm

D

104 ppm

Text Solution

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The correct Answer is:
To find the concentration of the solution in parts per million (ppm), we can follow these steps: ### Step 1: Understand the formula for concentration in ppm The formula to calculate the concentration in ppm is given by: \[ \text{ppm} = \left( \frac{\text{mass of solute}}{\text{mass of solution}} \right) \times 10^6 \] ### Step 2: Identify the mass of solute and mass of solution From the question, we have: - Mass of solute (BaCl₂) = 1.04 g - Mass of solution = \(10^5\) g ### Step 3: Substitute the values into the formula Now, we can substitute the values into the ppm formula: \[ \text{ppm} = \left( \frac{1.04 \, \text{g}}{10^5 \, \text{g}} \right) \times 10^6 \] ### Step 4: Calculate the concentration Now, we perform the calculation: \[ \text{ppm} = \left( \frac{1.04}{10^5} \right) \times 10^6 \] \[ = \left( 1.04 \times 10^1 \right) = 10.4 \, \text{ppm} \] ### Step 5: State the final answer Therefore, the concentration of the barium chloride solution is: \[ \text{Concentration} = 10.4 \, \text{ppm} \]
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