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The elevation in boiling point of a solu...

The elevation in boiling point of a solution of 9.43 g of `MgCl_2` in 1 kg of water is ( `K_b` = 0.52 K kg `mol^(-1)` , Molar mass of `MgCl_2 = 94.3 g mol^(-1)`)

A

0.156

B

0.52

C

0.17

D

0.94

Text Solution

Verified by Experts

The correct Answer is:
A
`MgCl_2 hArr Mg^(2+) + 2Cl^(-) , i=3`
`DeltaT_b=iK_bm=3xx0.52xx9.43/(94.3xx1)`=0.156
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