The values of van't Hoff factors for KCl, NaCl and `K_2SO_4` , respectively , are ___

Options

A. 2,2 and 2
B. 2,2 and 3
C. 1,1 and 2
D. 1,1 and 1

Explanation

To determine the van't Hoff factors for KCl, NaCl, and K2SO4, we need to analyze how these compounds dissociate in solution.

### Step-by-Step Solution:

1. **Understanding van't Hoff Factor (i)**:
The van't Hoff factor (i) is defined as the number of particles into which a solute dissociates in solution. For ionic compounds, this is determined by the number of ions produced when the compound dissolves.

2. **Calculating for KCl**:
- KCl dissociates in water as follows:
\[ KCl \rightarrow K^+ + Cl^- \]
- This results in 2 ions: one potassium ion (K⁺) and one chloride ion (Cl⁻).
- Therefore, the van't Hoff factor (i) for KCl is:
\[ i = 2 \]

3. **Calculating for NaCl**:
- NaCl also dissociates in water as follows:
\[ NaCl \rightarrow Na^+ + Cl^- \]
- Similar to KCl, this results in 2 ions: one sodium ion (Na⁺) and one chloride ion (Cl⁻).
- Therefore, the van't Hoff factor (i) for NaCl is:
\[ i = 2 \]

4. **Calculating for K2SO4**:
- K2SO4 dissociates in water as follows:
\[ K2SO4 \rightarrow 2K^+ + SO_4^{2-} \]
- This results in 3 ions: two potassium ions (K⁺) and one sulfate ion (SO₄²⁻).
- Therefore, the van't Hoff factor (i) for K2SO4 is:
\[ i = 3 \]

5. **Final Answer**:
- The values of van't Hoff factors for KCl, NaCl, and K2SO4 are:
\[ \text{KCl: } 2, \text{ NaCl: } 2, \text{ K2SO4: } 3 \]

### Summary:
The van't Hoff factors for KCl, NaCl, and K2SO4 are 2, 2, and 3, respectively.

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