Value of Henry's constant `K_(H)`…

Options

A. increases with increase in temperature
B. decreases with increase in temperature
C. remains constant
D. first increases then decreases

Answer

To solve the question regarding the value of Henry's constant \( K_H \) and its behavior with temperature, we can follow these steps:

### Step 1: Understand Henry's Law
Henry's Law states that the solubility of a gas in a liquid is directly proportional to the partial pressure of that gas above the liquid. Mathematically, it can be expressed as:
\[ P = K_H \cdot X \]
where:
- \( P \) is the partial pressure of the gas,
- \( K_H \) is Henry's constant, and
- \( X \) is the mole fraction of the gas in the liquid.

### Step 2: Analyze the Relationship
From the equation \( P = K_H \cdot X \), we can see that as the pressure \( P \) increases, the solubility \( X \) of the gas also increases, assuming \( K_H \) remains constant.

### Step 3: Consider the Effect of Temperature
Henry's constant \( K_H \) is influenced by temperature. Generally, as the temperature of a solution increases, the solubility of gases decreases. This implies that \( K_H \) increases with an increase in temperature.

### Step 4: Conclusion
Thus, we conclude that:
- As temperature increases, the value of Henry's constant \( K_H \) increases.

### Final Answer
The correct statement regarding Henry's constant is that \( K_H \) increases with an increase in temperature.

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