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On the basic of information given below mark the Correct option .Information:
(P)In bromoethane and choroethane mixture intermolar interactions of A.A and B.B tupesare nearly same as A .B type intersections.
(Q) In ethanol and acetone mixture A.A or B.B type inetermolecular interaction are stronger than A.B type interactions.
(R) In chloroform and acetone mixture A.A or B.B type intermolecular interactions are weaker than A. B type interactions.

A

Solution (II) and (III) will follow Raoult's law

B

Solution (I) will follow Raoult's law

C

Solution (II) will show negative deviation from Raoult's law .

D

Solution (III) will show positive deviation from Raoult's law .

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we will analyze the information given in statements P, Q, and R regarding the intermolecular interactions in different mixtures. ### Step-by-Step Solution: 1. **Understanding Statement P**: - Statement P mentions that in a mixture of bromoethane and chloroethane, the intermolecular interactions of A-A and B-B types are nearly the same as A-B type interactions. - This indicates that the solution behaves ideally, meaning the interactions are similar and there is no significant deviation from Raoult's law. - **Conclusion**: This represents an ideal solution. 2. **Understanding Statement Q**: - Statement Q states that in a mixture of ethanol and acetone, the A-A or B-B type intermolecular interactions are stronger than A-B type interactions. - This suggests that the solution does not behave ideally, as the stronger A-A and B-B interactions lead to a positive deviation from Raoult's law. - **Conclusion**: This represents a non-ideal solution with positive deviation. 3. **Understanding Statement R**: - Statement R indicates that in a mixture of chloroform and acetone, the A-A or B-B type intermolecular interactions are weaker than A-B type interactions. - This implies that the solution also does not behave ideally, but in this case, it shows a negative deviation from Raoult's law. - **Conclusion**: This represents a non-ideal solution with negative deviation. 4. **Analyzing the Options**: - Based on the conclusions drawn from P, Q, and R: - **Option 1**: Incorrect, as only the solution in statement P follows Raoult's law. - **Option 2**: Correct, as the solution in statement P is the only one that follows Raoult's law. - **Option 3**: Incorrect, as the solution in statement Q shows positive deviation, not negative. - **Option 4**: Incorrect, as the solution in statement R shows negative deviation, not positive. 5. **Final Conclusion**: - The correct option is **Option 2**, which states that only the solution in statement P follows Raoult's law.

To solve the question, we will analyze the information given in statements P, Q, and R regarding the intermolecular interactions in different mixtures. ### Step-by-Step Solution: 1. **Understanding Statement P**: - Statement P mentions that in a mixture of bromoethane and chloroethane, the intermolecular interactions of A-A and B-B types are nearly the same as A-B type interactions. - This indicates that the solution behaves ideally, meaning the interactions are similar and there is no significant deviation from Raoult's law. - **Conclusion**: This represents an ideal solution. ...
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On the basic of information given below mark the Correct option .Information: (P)In bromoethane and choroethane mixture intermolar interactions of A.A and B.B is nearly same as A .B type intersections. (Q) In ethanol and acetone mixture A.A or B.B type inetermolecular interaction are stronger than A.B type interactions. (R) In chloroform and acetone mixture A.A or B.B type intermolecular interactions are weaker than A. B type interactions.

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