If two liquids A and B from minimum boiling azeotrope at some specific composition then

Options

A. A-B interactions are stronger than those between A-A or B-B
B. vapour pressure of solution increases because more number of molecules of liquids A and B can escape from the solution
C. vapour pressure of solution decreases because less number of molecules of only one of the liquids escape from the solution.
D. A-B interactions are weaker than those between A-A and B-B

Explanation

To solve the question regarding the formation of a minimum boiling azeotrope between two liquids A and B, we need to understand the concepts related to Raoult's law and the nature of interactions between the molecules of the liquids involved.

### Step-by-Step Solution:

1. **Understanding Azeotropes**:
- Azeotropes are mixtures of two or more liquids that boil at a constant temperature and maintain the same composition in the vapor phase as in the liquid phase. Minimum boiling azeotropes occur when the boiling point of the mixture is lower than that of either pure component.

**Hint**: Recall that azeotropes can be classified into minimum boiling and maximum boiling types based on their boiling point behavior.

2. **Raoult's Law**:
- Raoult's law states that the vapor pressure of a component in a solution is directly proportional to its mole fraction in the solution. For ideal solutions, the interactions between different molecules are similar to those between like molecules.

**Hint**: Consider how deviations from Raoult's law indicate the strength of interactions between different types of molecules.

3. **Positive Deviation from Raoult's Law**:
- When two liquids form a minimum boiling azeotrope, they exhibit a large positive deviation from Raoult's law. This means that the vapor pressure of the mixture is higher than what would be expected based on the individual components.

**Hint**: Think about the implications of positive deviation on the interactions between the molecules.

4. **Bond Interactions**:
- In the case of positive deviation, the interactions between the different types of molecules (AB interactions) are weaker than the interactions between like molecules (AA and BB interactions). This leads to an increase in vapor pressure and a lower boiling point for the mixture.

**Hint**: Analyze how the strength of intermolecular forces affects the boiling point of the mixture.

5. **Conclusion**:
- Therefore, for two liquids A and B that form a minimum boiling azeotrope, the statement that is correct is that the AB bond interactions are weaker than the AA or BB bond interactions. This is consistent with the behavior of mixtures that exhibit positive deviation from Raoult's law.

**Hint**: Remember that the nature of the interactions dictates the boiling point behavior of the solution.

### Final Answer:
The correct statement is that the AB bond interactions are weaker than the AA or BB bond interactions, leading to the formation of a minimum boiling azeotrope.