Home
Class 12
CHEMISTRY
Assertion:The vapour pressure of an aque...

Assertion:The vapour pressure of an aqueous solution of sucrose is less than 1.013 bar at 373.15 K
Reason : Vapour pressure of water is 1.013 bar at 373.15 K.

A

If both assertion and reason are true and reason is the correct explanation of assertion

B

If both assertion and reason are true but reason is not the correct explanation of assertion.

C

If assertion is true but reason is false

D

If both assertion and reason are false

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze both the assertion and the reason provided. ### Step 1: Understand the Assertion The assertion states that the vapor pressure of an aqueous solution of sucrose is less than 1.013 bar at 373.15 K. **Explanation**: - At 373.15 K (which is the boiling point of water), the vapor pressure of pure water is 1.013 bar. - When a non-volatile solute like sucrose is dissolved in water, it lowers the vapor pressure of the solution compared to that of pure water. ### Step 2: Understand the Reason The reason states that the vapor pressure of water is 1.013 bar at 373.15 K. **Explanation**: - This statement is correct. The vapor pressure of pure water at its boiling point (373.15 K) is indeed 1.013 bar. ### Step 3: Analyze the Relationship Between Assertion and Reason - The assertion is correct because the vapor pressure of the sucrose solution is indeed less than that of pure water (1.013 bar). - The reason is also correct as it correctly states the vapor pressure of pure water at 373.15 K. ### Step 4: Determine if the Reason Explains the Assertion While both statements are correct, the reason does not fully explain why the vapor pressure of the sucrose solution is less than that of pure water. It does not mention that sucrose is a non-volatile solute, which is the key factor in lowering the vapor pressure. ### Conclusion - Both the assertion and the reason are correct. - However, the reason does not adequately explain the assertion. ### Final Answer - Assertion: True - Reason: True - Explanation: The reason does not explain the assertion.

To solve the question, we need to analyze both the assertion and the reason provided. ### Step 1: Understand the Assertion The assertion states that the vapor pressure of an aqueous solution of sucrose is less than 1.013 bar at 373.15 K. **Explanation**: - At 373.15 K (which is the boiling point of water), the vapor pressure of pure water is 1.013 bar. - When a non-volatile solute like sucrose is dissolved in water, it lowers the vapor pressure of the solution compared to that of pure water. ...
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    NCERT FINGERTIPS ENGLISH|Exercise Types Of Solution|3 Videos
  • SOLUTIONS

    NCERT FINGERTIPS ENGLISH|Exercise Expressing Concentration Of Solutions|16 Videos
  • SOLUTIONS

    NCERT FINGERTIPS ENGLISH|Exercise EXEMPLAR PROBLEMS|24 Videos
  • PRACTICE PAPER -3

    NCERT FINGERTIPS ENGLISH|Exercise Practice Paper 3|50 Videos
  • SURFACE CHEMISTRY

    NCERT FINGERTIPS ENGLISH|Exercise Assertion And Reason|15 Videos

Similar Questions

Explore conceptually related problems

The vapour pressure of a dilute aqueous solution of glucose is 750 mmHg at 373 K. The mole fraction of the solute is

If the vapor pressure of a dilute aqueous solution of glucose is 750 mm of Hg at 373 K , then molality of solute is

Calculate the vapour pressure of an aqueous solution of 1.0 molal glucose solution at 100^(@)C .

The vapour pressure of an aqueous solution of glucose is 750 mm of Hg at 373 K . Calculate molality and mole fraction of solute.

Urea forms an ideal solution. Determine the vapour pressure of an aqueous solution containing 10 per cent by mass of urea at 40^(@)C (Vapour pressure of water at 40^(@)C=55.3mm Hg ).

The total vapour pressure of a 4 mole % solution of NH_(3) in water at 293 K is 50.0 torr. The vapour pressure of pure water is 17.0 torr at this temperature . Applying Henry's and Raoult's law, calculate the total vapour pressure for a 5 mole % solution:

The vapour pressure of a dilute aqueous solution of glucose is 700 mm of Hg at 373 K . Calculate the (a) molality and (b) mole fraction of the solute.

The vapour pressure of a 5% aqueous solution of a non-volatile organic substance at 373 K . Is 745 mm . Calculate the molecular mass of the solute.

Calculate the vapour pressure of 10% (w/w) aqueous glucose solution at 30^@C , if vapour pressure of pure water is 31.8 mm.

Assuming ideal behaviour, calculate the vapour pressure of 1.0 molal solution of a non-volatile molecular solute in water at 50^@C . The vapour pressure of water at 50^@C is 0.122 atm.