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When an aqueous solution of AgNO3 is ele...

When an aqueous solution of `AgNO_3` is electroysed between platinum electrodes, the substances liberted at anode and cathode are

A

silver is deposited at cathode and `O_2` is liberated at anode

B

silver is deposited at cathode and `H_2` is liberated at anode

C

hydrogen is liberted at cathode and `O_2` is liberated at anode.

D

silver is deposited at cathode and Pt is dissolved in electrolyte.

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To solve the question regarding the electrolysis of an aqueous solution of `AgNO3` between platinum electrodes, we will analyze the reactions occurring at both the anode and cathode. ### Step-by-Step Solution: 1. **Identify the Electrolyte and Its Components:** - The electrolyte is `AgNO3`, which dissociates in water to give `Ag^+` (silver ions) and `NO3^-` (nitrate ions). 2. **Determine the Reactions at the Cathode:** - At the cathode, reduction occurs. The possible cations in the solution are `Ag^+` and `H^+` (from water). - The standard reduction potentials (E°) for these reactions are: - For `Ag^+ + e^- → Ag (s)`, E° = +0.80 V (approximately) - For `2H^+ + 2e^- → H2 (g)`, E° = 0.00 V - Since `Ag^+` has a higher reduction potential, it will be reduced preferentially. - Therefore, the reaction at the cathode is: \[ Ag^+ + e^- \rightarrow Ag (s) \] 3. **Determine the Reactions at the Anode:** - At the anode, oxidation occurs. The possible anions in the solution are `NO3^-` and `OH^-` (from water). - The standard oxidation potentials for these reactions are: - For `2OH^- → O2 (g) + 2H^+ + 4e^-`, E° = -0.40 V (approximately) - For `NO3^-` oxidation, the potential is generally lower than that of `OH^-`. - Since `OH^-` has a lower discharge potential, it will be oxidized preferentially. - Therefore, the reaction at the anode is: \[ 2OH^- \rightarrow O2 (g) + 2H2O + 4e^- \] 4. **Summarize the Products:** - At the cathode: Silver (Ag) is deposited. - At the anode: Oxygen (O2) is liberated. 5. **Conclusion:** - The substances liberated at the anode and cathode during the electrolysis of `AgNO3` are: - **Anode:** Oxygen (O2) - **Cathode:** Silver (Ag) ### Final Answer: - At the anode, oxygen is liberated, and at the cathode, silver is deposited.

To solve the question regarding the electrolysis of an aqueous solution of `AgNO3` between platinum electrodes, we will analyze the reactions occurring at both the anode and cathode. ### Step-by-Step Solution: 1. **Identify the Electrolyte and Its Components:** - The electrolyte is `AgNO3`, which dissociates in water to give `Ag^+` (silver ions) and `NO3^-` (nitrate ions). 2. **Determine the Reactions at the Cathode:** ...
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