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Electrolysis of an aqueous solution of A...

Electrolysis of an aqueous solution of `AgNO_3` with silver electrodes produce __(i)___ at cathode while ___(ii)___ ions are dissolved from anode. When Pt electrodes are used ____(iii)___ is produced at anode ___(iv)___ at cathode.

A

`{:("(i)","(ii)","(iii)","(iv)"),(H_2,NO_3^(-) , OH^(-), H_2):}`

B

`{:("(i)","(ii)","(iii)","(iv)"),(Ag,H^+, O_2, H_2):}`

C

`{:("(i)","(ii)","(iii)","(iv)"),(Ag,H^(+),O_(2),Ag):}`

D

`{:("(i)","(ii)","(iii)","(iv)"),("Ag","H"^(+),"Ag"^(+),"O"_(2)):}`

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The correct Answer is:
To solve the question regarding the electrolysis of an aqueous solution of AgNO₃ with silver electrodes, let's break it down step by step. ### Step-by-Step Solution: 1. **Identify the Electrolysis Process**: - Electrolysis involves the breakdown of a compound in solution using an electric current. In this case, we are dealing with an aqueous solution of silver nitrate (AgNO₃). 2. **Electrodes Used**: - The question specifies that silver electrodes are used initially. This means that both the anode and cathode are made of silver. 3. **Reactions at the Cathode**: - At the cathode, reduction occurs. The silver ions (Ag⁺) in the solution gain electrons to form solid silver (Ag). - The half-reaction can be written as: \[ \text{Ag}^+ + e^- \rightarrow \text{Ag} \] - Therefore, the product at the cathode is **silver (Ag)**. 4. **Reactions at the Anode**: - At the anode, oxidation occurs. Silver from the electrode dissolves into the solution as silver ions (Ag⁺). - The half-reaction can be written as: \[ \text{Ag} \rightarrow \text{Ag}^+ + e^- \] - Thus, silver ions (Ag⁺) are dissolved from the anode. 5. **Using Platinum Electrodes**: - When platinum electrodes are used instead of silver, the reactions change slightly. At the cathode, silver ions (Ag⁺) are still reduced to form solid silver (Ag). - At the anode, water undergoes oxidation to produce oxygen gas (O₂) and hydrogen ions (H⁺). - The half-reaction for the anode can be written as: \[ 2 \text{H}_2\text{O} \rightarrow \text{O}_2 + 4 \text{H}^+ + 4 e^- \] - Thus, the product at the anode is **oxygen gas (O₂)**. ### Final Answers: - (i) Ag (silver) is produced at the cathode. - (ii) Ag⁺ (silver ions) are dissolved from the anode. - (iii) O₂ (oxygen gas) is produced at the anode when platinum electrodes are used. - (iv) Ag (silver) is produced at the cathode. ### Summary of Answers: - (i) Ag - (ii) Ag⁺ - (iii) O₂ - (iv) Ag
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