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How long will it take for a uniform curr...

How long will it take for a uniform current of 6.0 ampere to deposit 78.0 g gold from a solution of `AuCl_(4)^(-)` ? What mass of chlorine gas will be formed simultaneously at the anode in the electrolytic cell ?

A

t = 3010 sec, w = 35.50 g

B

t = 20306 sec, w = 45.54 g

C

t = 19500 sec, w = 54.5 g

D

t = 19139 sec, w = 42.24 g

Text Solution

Verified by Experts

The correct Answer is:
D
Reactions take place at electrodes are : At cathode : `AuCl_4^(-) + 3e^(-) to Au + 4Cl^(-)`
At anode : `Cl^(-) to 1/2Cl_2 + e^(-)`
For the deposition of 197 g ( 1 mole ) of Au = 3F of charge is required thus, for the deposition of 78 g of Au , Charge required =`3/197xx78`=1.19 F = 1.19 x 96500 coulombs
From Q=I x t
`t=Q/t=(1.19xx96500)/6`=19136.16 sec
By 1 F charge , 35.5 g of `Cl_2` gas is formed , thus from 1.19 F, mass of chlorine gas formed = 35.5 x 1.19 = 42.24 g
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