In a reaction, `2X to Y`, the concentration of X decreases from 0.50M to 0.38 M in 10 min. What is the rate of reaction in M `s^(-1)` during this interval?

Options

A. `2 xx 10^(-4)`
B. `4 xx 10^(-2)`
C. `2 xx 10^(-2)`
D. `1 xx 10^(-2)`

Answer

A

Explanation

Rate of reaction `= (Delta[X])/(Delta t)`
`Delta [X] = X_(i) - X_(f) = 0.50 - 0.38 = 0.12 M`
Rate `= (0.12)/(10 xx 60) = 2 xx 10^(-4) M s^(-1)`