The hydrolysis of ethyl acetate is a reaction of :
` CH_(3)COOC_(2)H_(5)+H_(2)Ooverset(H^(+))rarr CH_(3)COOH+C_(2)H_(5)OH`

Options

A. zero order
B. pseudo first order
C. second order
D. third order

Answer

To determine the order of the hydrolysis of ethyl acetate, we can analyze the reaction step by step.

### Step 1: Write the Reaction
The hydrolysis of ethyl acetate can be represented as:
\[ \text{CH}_3\text{COOC}_2\text{H}_5 + \text{H}_2\text{O} \overset{H^+}{\rightarrow} \text{CH}_3\text{COOH} + \text{C}_2\text{H}_5\text{OH} \]

### Step 2: Identify the Reactants and Products
In this reaction, the reactants are ethyl acetate (CH₃COOC₂H₅) and water (H₂O), and the products are acetic acid (CH₃COOH) and ethanol (C₂H₅OH).

### Step 3: Consider the Reaction Medium
The reaction occurs in an aqueous medium where water is present in excess. This means that the concentration of water does not change significantly during the reaction and can be considered constant.

### Step 4: Rate Expression
Since water is in excess, we can simplify the rate expression. The rate of the reaction can be expressed in terms of the concentration of ethyl acetate:
\[ \text{Rate} = k' [\text{CH}_3\text{COOC}_2\text{H}_5] \]
where \( k' \) is the effective rate constant that includes the concentration of water.

### Step 5: Determine the Order of the Reaction
The rate expression indicates that the rate of the reaction depends only on the concentration of ethyl acetate. Therefore, this reaction is first-order with respect to ethyl acetate.

### Conclusion
The hydrolysis of ethyl acetate is a first-order reaction.

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