For a reaction `A_(2) + B_(2) hArr 2AB` the figure shows the path of the reaction in absence and presence of a catalyst. What will be energy of activation for forward `(E_(f))` and backward `(E_(b))` reaction in presence of a catalyst and `Delta H` for the reaction? The dotted curve is path of reaction in presence of a catalyst.

Options

A. `E_(f) = 60 kJ// mol, E_(b) = 70 kJ // mol, Delta H = 20 kJ// mol`
B. `E_(f) = 20 kJ mol, E_(b) = 2- kJ// mol, Delta H = 50 kJ//mol`
C. `E_(f) = 70 kJ//mol, E_(b) = 20 kJ//mol, Delta H = 10 kJ//mol`
D. `E_(f) = 10 kJ//mol, E_(b) = 20 kJ//mol, Delta H = - 10 kJ mol`

Answer

D

Explanation

`E_(f) = 70 - 60 = 10 `kj/mol
`E_(b) = 70 - 50 = 20` kj/mol
`Delta H = 50 - 60 = - 10` kj/mol