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Among the electrolytes Na(2),SO(4),CaCl(...

Among the electrolytes `Na_(2),SO_(4),CaCl_(2),Al_(2)(SO_(4))_(3) and NH_(4)Cl`, the most effective coagulating agent for `Sb_(2)S_(3)` sol is

A

`Na_(2)SO_(4)`

B

`CaCl_(2)`

C

`Al_(2)(SO_(4))_(3)`

D

`NH_(4)Cl`

Text Solution

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The correct Answer is:
To determine the most effective coagulating agent for the `Sb2S3` sol among the given electrolytes (`Na2SO4`, `CaCl2`, `Al2(SO4)3`, and `NH4Cl`), we can follow these steps: ### Step 1: Identify the nature of the sol `Sb2S3` is a negatively charged colloidal sol. This means that to coagulate it, we need a positively charged ion that can neutralize the negative charge of the sol. **Hint:** Remember that coagulation occurs when oppositely charged ions neutralize the charge of the colloidal particles. ### Step 2: Analyze the electrolytes We will analyze the electrolytes based on the charge of their cations: - `Na2SO4` dissociates into `2Na^+` and `SO4^2-`. - `CaCl2` dissociates into `Ca^2+` and `2Cl^-`. - `Al2(SO4)3` dissociates into `2Al^3+` and `3SO4^2-`. - `NH4Cl` dissociates into `NH4^+` and `Cl^-`. **Hint:** Focus on the cations of each electrolyte, as they will determine the coagulating power. ### Step 3: Determine the charge and valency of cations The cations and their charges are: - `Na^+` (valency = 1) - `Ca^2+` (valency = 2) - `Al^3+` (valency = 3) - `NH4^+` (valency = 1) **Hint:** Higher valency cations have a greater coagulating power due to their ability to neutralize more negative charges. ### Step 4: Apply Hardy-Schulze Rule According to the Hardy-Schulze rule, the coagulating power of an electrolyte is directly proportional to the valency of the active ion. Therefore, the order of coagulating power based on the cations is: 1. `Al^3+` (highest coagulating power) 2. `Ca^2+` 3. `Na^+` 4. `NH4^+` **Hint:** The greater the charge of the cation, the more effective it is at coagulating the negatively charged sol. ### Step 5: Conclusion Since `Al^3+` from `Al2(SO4)3` has the highest valency among the cations, it will be the most effective coagulating agent for `Sb2S3` sol. Thus, the most effective coagulating agent for `Sb2S3` sol is **`Al2(SO4)3`**. **Final Answer:** `Al2(SO4)3` (Option C)

To determine the most effective coagulating agent for the `Sb2S3` sol among the given electrolytes (`Na2SO4`, `CaCl2`, `Al2(SO4)3`, and `NH4Cl`), we can follow these steps: ### Step 1: Identify the nature of the sol `Sb2S3` is a negatively charged colloidal sol. This means that to coagulate it, we need a positively charged ion that can neutralize the negative charge of the sol. **Hint:** Remember that coagulation occurs when oppositely charged ions neutralize the charge of the colloidal particles. ### Step 2: Analyze the electrolytes ...
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