`V_2O_5` reacts with alkalies as well as acids to give

Options

A. `VO_4^(3-) and VO^(2+)`
B. `VO^(2+) and VO_4^(+)`
C. `VO_2^(+) and VO^(2+)`
D. `VO_4^(3-) and VO_4^(+)`

Answer

To solve the question regarding the reaction of \( V_2O_5 \) with acids and alkalis, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Nature of \( V_2O_5 \)**:
- \( V_2O_5 \) is known to be an amphoteric oxide, meaning it can react with both acids and bases.

2. **Reaction with Acids**:
- When \( V_2O_5 \) reacts with an acid (for example, hydrochloric acid, \( HCl \)), it forms vanadyl ions. The reaction can be represented as:
\[ V_2O_5 + 6HCl \rightarrow 2VOCl_3 + 3H_2O \]
- In this case, the vanadyl ion \( VO^{3+} \) is formed.

3. **Reaction with Alkalis**:
- When \( V_2O_5 \) reacts with a base (for example, sodium hydroxide, \( NaOH \)), it forms vanadate ions. The reaction can be represented as:
\[ V_2O_5 + 2NaOH + 3H_2O \rightarrow 2NaVO_3 + 2H_2O \]
- Here, the vanadate ion \( VO_4^{3-} \) is formed.

4. **Conclusion**:
- Since \( V_2O_5 \) can react with both acids and bases to form \( VO^{3+} \) and \( VO_4^{3-} \), it confirms that \( V_2O_5 \) is amphoteric in nature.

5. **Final Answer**:
- The correct answer to the question is that \( V_2O_5 \) reacts with acids to give \( VO^{3+} \) and with alkalis to give \( VO_4^{3-} \).