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The number of moles of KMnO(4) that will...

The number of moles of `KMnO_(4)` that will be needed to react completely with one mole of ferrous oxalate in acidic solution is:

A

`3//5`

B

`2//5`

C

`4//5`

D

1

Text Solution

Verified by Experts

The correct Answer is:
A

`Fe^(2+)+C_2O_4^(2-) to Fe^(3+)+2CO_2+3e^(-)`
`MnO_4^(-)+5e^(-) to Mn^(2+)`
1 mole of `KMnO_4` accpts 5 electrons
1 mole of ferrous oxalate loses 3 electrons
`5e^(-)-=1` mole of `KMnO_4`
`3e^(-)` will equivalent to 3/5 mole of `KMnO_4`
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