When an oxide of manganese (P) is fused with KOH in the presence of an oxidising agent and dissolved in water, it gives a dark green solution of compound (Q). Compound (Q) disproportionates in neutral or acidic solution to give purple compound ( R) oxidises potassium iodide solution to a compound (S) and compound (P) is also formed. Compounds P to S are

Options

A. `{:(" "P," "Q," "R," "S),(MnO_4^(-),KIO_3,MnO_2,K_2MnO_4):}`
B. `{:(" "P," "Q," "R," "S),(MnO_2,K_2MnO_4,MnO_4^(-),KIO_3):}`
C. `{:(" "P," "Q," "R," "S),(MnO_2,MnO_4^(-),K_2MnO_4,KIO_3):}`
D. `{:(" "P," "Q," "R," "S),(K_2MnO_4,MnO_2,MnO_4^(-),KIO_3):}`

Answer

B

Explanation

`P=MnO_2, Q=K_2MnO_4,R=KMnO_4,S=KIO_3`
`underset((P))(2KMnO_4)oversetDeltatounderset((Q))(K_2MnO_4)+2H_2O`
`3MnO_4^(2-)+4H^(+)to underset((R))(2MnO_2)^(-)+MnO_2+2H_2O`