The correct configuration of f-block elements is

Options

A. `(n-2)f^(1-14)(n-1)d^(0-1)ns^2`
B. `(n-1)f^(1-14)(n-1)d^(0-1)ns^2`
C. `(n-3)f^(1-14)(n-2)d^(0-1)(n-1)s^2`
D. `(n-2)f^(0-1)(n-1)d^(0-1)ns^2`

Answer

To determine the correct electronic configuration of f-block elements, we need to follow these steps:

### Step 1: Understand the f-block elements
The f-block elements consist of the lanthanides and actinides. The distinguishing feature of these elements is that their last electrons enter the f subshell.

### Step 2: Identify the principal quantum number (n)
In the electronic configuration of f-block elements, the principal quantum number (n) is crucial. The f-block elements have configurations where the last electrons fill the f subshell, which is associated with the principal quantum number \( n-2 \).

### Step 3: Determine the filling order of subshells
For f-block elements, the filling order of the subshells is as follows:
- The f subshell can hold a maximum of 14 electrons (from f1 to f14).
- The d subshell can hold a maximum of 10 electrons (from d0 to d1).
- The s subshell can hold a maximum of 2 electrons (s2).

### Step 4: Write the general electronic configuration
The general electronic configuration for f-block elements can be summarized as:
- \( [n-2]f^{1-14} [n-1]d^{0-1} [n]s^2 \)

This means:
- The f subshell is filled with 1 to 14 electrons.
- The d subshell can have 0 or 1 electron.
- The s subshell is filled with 2 electrons.

### Step 5: Identify the correct option
Based on the above information, we can conclude that the correct electronic configuration for f-block elements is:
- \( [n-2]f^{1-14} [n-1]d^{0-1} [n]s^2 \)

Thus, the correct option regarding the electronic configuration of f-block elements is the one that matches this format.