The electronic configurationo of Cu(II) is `3d^(9)` whereas that of Cu(I) is `3d^(10)`. Which of the following is correct ?

Options

A. Cu(II) is more stable.
B. Cu(II) is less stable.
C. Cu(I) and Cu(II) are equally stable.
D. Stability of Cu(I) and Cu(II) depends on nature of copper salts.

Explanation

To determine the correct statement regarding the stability of Cu(I) and Cu(II), we need to analyze their electronic configurations and the factors affecting their stability.

### Step-by-Step Solution:

1. **Identify the Electronic Configurations:**
- The electronic configuration of Cu(I) is \(3d^{10}\).
- The electronic configuration of Cu(II) is \(3d^{9}\).

2. **Stability Considerations:**
- Generally, half-filled and fully filled subshells are more stable due to symmetry and exchange energy. Therefore, \(3d^{10}\) (Cu(I)) is more stable than \(3d^{9}\) (Cu(II)) in an isolated environment.

3. **Aqueous Solution Behavior:**
- In aqueous solutions, Cu(I) can undergo disproportionation, meaning it can oxidize to Cu(II) and reduce to Cu(0). This reaction indicates that Cu(I) is less stable in aqueous solutions because it can easily convert to Cu(II).
- Therefore, in aqueous solutions, Cu(II) is more stable than Cu(I).

4. **Non-Aqueous Solution Behavior:**
- In non-aqueous solutions, Cu(I) is generally more stable than Cu(II) because the tendency for disproportionation is reduced. Thus, Cu(I) retains its stability due to its fully filled \(3d^{10}\) configuration.

5. **Conclusion:**
- The stability of Cu(I) and Cu(II) depends on the environment (aqueous vs. non-aqueous). In aqueous solutions, Cu(II) is more stable, while in non-aqueous solutions, Cu(I) is more stable.

### Final Statement:
The correct conclusion is that the stability of Cu(I) and Cu(II) depends on the nature of the solution. In aqueous solutions, Cu(II) is more stable, while in non-aqueous solutions, Cu(I) is more stable.