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Which of the following statements is not...

Which of the following statements is not correct?

A

Copper liberates hydrogen from acids.

B

In higher oxidation states, manganese forms stable compounds with oxygen and fluorine.

C

`Mn^(3+) and Co^(3+)` are oxidising agents in aqueous solution.

D

`Ti^(2+) and Cr^(2+)` are reducing agents in aqueous solution.

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AI Generated Solution

The correct Answer is:
To determine which statement is not correct among the options provided, we will analyze each statement one by one. ### Step-by-Step Solution: 1. **Analyze Statement 1: "Copper liberates hydrogen from acids."** - Copper (Cu) is a transition metal with a standard reduction potential greater than that of hydrogen ions (H⁺). The standard reduction potential for copper is positive, while that for hydrogen is zero. This means that copper cannot reduce hydrogen ions to liberate hydrogen gas. - Therefore, this statement is **incorrect**. 2. **Analyze Statement 2: "The higher oxidation state of manganese forms stable compounds with oxygen and chlorine."** - Manganese can exhibit various oxidation states, with +7 being the highest. In this state, manganese forms stable compounds such as permanganate (MnO₄⁻) with oxygen. It also forms stable compounds with fluorine and chlorine. - Thus, this statement is **correct**. 3. **Analyze Statement 3: "Mn³⁺ and Co³⁺ are oxidizing agents in aqueous solution."** - Mn³⁺ can act as an oxidizing agent because it can be reduced to Mn²⁺. Similarly, Co³⁺ can also act as an oxidizing agent, being reduced to Co²⁺. Both ions can oxidize other substances while being reduced themselves. - Therefore, this statement is **correct**. 4. **Analyze Statement 4: "Ti²⁺ and Cr²⁺ are reducing agents in aqueous solution."** - Ti²⁺ and Cr²⁺ represent the +2 oxidation states of titanium and chromium, respectively. These ions can act as reducing agents because they can be oxidized to higher oxidation states (Ti³⁺ and Cr³⁺). - Thus, this statement is **correct**. ### Conclusion: After analyzing all statements, we find that the first statement, "Copper liberates hydrogen from acids," is the only incorrect statement. ### Final Answer: The incorrect statement is **A: Copper liberates hydrogen from acids.** ---

To determine which statement is not correct among the options provided, we will analyze each statement one by one. ### Step-by-Step Solution: 1. **Analyze Statement 1: "Copper liberates hydrogen from acids."** - Copper (Cu) is a transition metal with a standard reduction potential greater than that of hydrogen ions (H⁺). The standard reduction potential for copper is positive, while that for hydrogen is zero. This means that copper cannot reduce hydrogen ions to liberate hydrogen gas. - Therefore, this statement is **incorrect**. ...
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NCERT FINGERTIPS ENGLISH-THE D- AND F- BLOCK ELEMENTS -EXEMPLER PROBLEMS
  1. Electronic confriguration of a transition element X in +3 oxidation st...

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  2. The electronic configurationo of Cu(II) is 3d^(9) whereas that of Cu(I...

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  3. Generally transition elements form coloured salts due to the presence ...

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  4. On addition of small amount of KMnO(4) to concentrated H(2)SO(4), a gr...

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  5. The magnetic nature of elements depends on the presence of unpaired el...

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  6. Which of the following oxidation state si common for all lanthanoids?

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  7. Which of the following reactions are disproportionation reactions? ...

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  8. When KMnO(4) solution is added to oxalic acid solution , the decolouri...

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  9. There are 14 elements in actinoid series. Which of the following eleme...

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  10. KMnO(4) acts as an oxidising agent in acidic medium. The number of mol...

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  11. Which of the following is an amphoteric oxide?

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  12. Gadolinium belongsd to 4f series. It's atomic number is 64. which of t...

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  13. Interstitial compounds are formed when small atoms are trapped inside ...

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  14. The magnetic moment is associated with its spin angular momentum and o...

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  15. KMnO(4) acts as on oxidising agent in alkaline medium. When alkaline K...

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  16. Which of the following statements is not correct?

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  17. When acidified K(2)Cr(2)O(7) solution is added to Sn^(2+) salts then S...

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  18. Higher oxidation state of manganese in fluoride is +4 (MnF(4)) but hig...

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  19. Although zirconium belongs to 4d transition series and hafnium to 5d t...

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  20. Why is HCl not used to make the medium acidic in oxidation reactions o...

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