When each of the following complex salts is treated with excess of `AgNO_(3)` solution, which will give the maximum amount of AgCl

Options

A. `[Co(NH_(3))_(6)]Cl_(6)`
B. `[Co(NH_(3))_(5)Cl]Cl_(2)`
C. `[Co(NH_(3))_(4)Cl_(2)]Cl`
D. `[Co(NH_(3))_(3)Cl_(3)]`

Answer

To determine which complex salt will yield the maximum amount of AgCl when treated with excess AgNO3 solution, we need to analyze the number of chloride ions (Cl⁻) present in each complex salt. The chloride ions that are outside the coordination sphere will react with AgNO3 to form AgCl.

Let's analyze each complex salt step by step:

### Step 1: Identify the complex salts and their chloride ions
1. **First complex salt: [Co(NH3)6]Cl3**
- Here, there are 3 chloride ions outside the coordination sphere.

2. **Second complex salt: [Co(NH3)5Cl]Cl2**
- In this case, there are 2 chloride ions outside the coordination sphere.

3. **Third complex salt: [Co(NH3)4Cl2]Cl**
- This complex has 1 chloride ion outside the coordination sphere.

4. **Fourth complex salt: [Co(NH3)6]NO3**
- There are no chloride ions in this complex, so it will not produce any AgCl.

### Step 2: Calculate the amount of AgCl produced
- **For [Co(NH3)6]Cl3**:
- 3 Cl⁻ ions will react with AgNO3 to produce 3 moles of AgCl.

- **For [Co(NH3)5Cl]Cl2**:
- 2 Cl⁻ ions will react with AgNO3 to produce 2 moles of AgCl.

- **For [Co(NH3)4Cl2]Cl**:
- 1 Cl⁻ ion will react with AgNO3 to produce 1 mole of AgCl.

- **For [Co(NH3)6]NO3**:
- 0 Cl⁻ ions will react, producing 0 moles of AgCl.

### Step 3: Compare the amounts of AgCl produced
- [Co(NH3)6]Cl3 → 3 moles of AgCl
- [Co(NH3)5Cl]Cl2 → 2 moles of AgCl
- [Co(NH3)4Cl2]Cl → 1 mole of AgCl
- [Co(NH3)6]NO3 → 0 moles of AgCl

### Conclusion
The complex salt that produces the maximum amount of AgCl when treated with excess AgNO3 is **[Co(NH3)6]Cl3**, yielding 3 moles of AgCl.

### Final Answer:
**[Co(NH3)6]Cl3 will give the maximum amount of AgCl.**

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