The denticity of the ligand `N(CH_(2)CH_(2)NH_(2))_(3)` is

Options

A. bidentate
B. tridentate
C. tetradentate
D. pentadentate.

Explanation

To determine the denticity of the ligand \( N(CH_2CH_2NH_2)_3 \), we need to analyze the structure and the number of donor atoms present in the ligand.

### Step-by-Step Solution:

1. **Identify the Ligand Structure**:
The ligand is \( N(CH_2CH_2NH_2)_3 \). This indicates that there is a central nitrogen atom (N) that is bonded to three ethylene diamine groups (each represented by \( CH_2CH_2NH_2 \)).

2. **Determine the Donor Atoms**:
Each ethylene diamine group \( CH_2CH_2NH_2 \) contains one nitrogen atom that can donate a lone pair of electrons to a metal center. Therefore, for each of the three groups, there is one donor nitrogen atom.

3. **Count the Total Donor Atoms**:
Since there are three ethylene diamine groups, and each contributes one nitrogen atom as a donor, we have:
\[ 3 \text{ (from each } CH_2CH_2NH_2 \text{ group)} + 1 \text{ (from the central nitrogen)} = 4 \text{ donor atoms.} \]

4. **Determine the Denticity**:
The denticity of a ligand is defined as the number of donor atoms that can coordinate to a central metal atom. In this case, since there are four donor nitrogen atoms, the ligand is classified as tetradentate.

5. **Conclusion**:
Therefore, the denticity of the ligand \( N(CH_2CH_2NH_2)_3 \) is **tetradentate**.

### Final Answer:
The denticity of the ligand \( N(CH_2CH_2NH_2)_3 \) is **tetradentate**.