The coordination number and the oxidation state of the element 'E' in the complex `[E(en)_2(C_2O_4)]NO_2` (where `(en)` is ethylenediamine) are, respectively

Options

A. 6 and 3
B. 6 and 2
C. 4 and 2
D. 4 and 3

Answer

A

Explanation

In the given complex `[E(en)_(2) (C_(2)O_(4))]^(+) NO_(2)^(-)` ethylenediamine is a bidentate ligand and `(C_(2)O_(4)^(2-))` oxalate ion is also bidentate ligand . Therefore , coordination number of the complex is 6 i.e., it is an octahedral complex .
Oxidation number of E in the given complex is
`x + 2 xx 0 + 1 xx (-2) = + 1`
`therefore x = 3`