Correct formula of tetraamminechloronitroplatinum (IV) sulphate can be written as

Options

A. `[Pt(NH_(3))_(4) (ONO)Cl]SO_(4)`
B. `[Pt(NH_(3))_(4) Cl_(2)NO_(2)]_(2)SO_(4)`
C. `[Pt(NH_(3))_(4) (NO_(2))Cl]SO_(4)`
D. `[PtCl(ONO)NH_(3)(SO_(4))]`

Answer

To determine the correct formula for tetraamminechloronitroplatinum (IV) sulphate, we can follow these steps:

### Step 1: Identify the components of the complex
The name "tetraamminechloronitroplatinum (IV) sulphate" indicates the following:
- **Tetraammine**: This means there are four ammonia (NH₃) ligands.
- **Chloro**: This indicates the presence of one chloride (Cl) ligand.
- **Nitro**: This indicates the presence of one nitro (NO₂) ligand.
- **Platinum (IV)**: This indicates that platinum is in the +4 oxidation state.
- **Sulphate**: This indicates the presence of a sulphate ion (SO₄²⁻).

### Step 2: Write the formula for the ligands and the metal
- The ammonia ligands contribute: 4 NH₃
- The chloride ligand contributes: 1 Cl
- The nitro ligand contributes: 1 NO₂
- The metal (platinum) is represented as Pt.

### Step 3: Combine the components
Now we combine these components in the correct order:
- The ligands are listed in alphabetical order: ammine (NH₃), chloro (Cl), nitro (NO₂).
- Thus, we write the formula as [Pt(NH₃)₄Cl(NO₂)].

### Step 4: Add the sulphate ion
Since the complex is associated with a sulphate ion (SO₄²⁻), we need to account for the charge:
- The platinum is in the +4 oxidation state, and the ligands (NH₃, Cl, NO₂) are neutral or have a charge of -1 for Cl and -1 for NO₂.
- The overall charge of the complex is +4 (from Pt) - 1 (from Cl) - 1 (from NO₂) = +2.
- To balance this with the sulphate ion (SO₄²⁻), we need one sulphate ion.

### Step 5: Write the final formula
The final formula for the complex will be:
\[ \text{[Pt(NH}_3\text{)}_4\text{Cl(NO}_2\text{)]SO}_4 \]

### Conclusion
Thus, the correct formula for tetraamminechloronitroplatinum (IV) sulphate is:
\[ \text{[Pt(NH}_3\text{)}_4\text{Cl(NO}_2\text{)]SO}_4 \]