Which of the following sets of examples and geometry of the compounds is not correct ?

Options

A. Octahedral - `[Co(NH_(3))_(6)]^(3+) , [Fe(CN)_(6)]^(3-)`
B. Square planar - `[Ni(CN)_(4)]^(2-) , [Cu(NH_(3))_(4)]^(2+)`
C. Tetrahedral - `[Ni(CO)_(4)] , [ZnCl_(4)]^(2-)`
D. Trigonal bipyramidal - `[Fe(NH_(3))_(6)]^(2+) , [CuCl_(4)]^(2-)`

Explanation

To solve the question regarding the incorrect relationship between coordination compounds and their geometries, we will analyze each option step by step.

### Step 1: Understand the Geometry and Coordination Number
- **Octahedral Geometry**: Requires a coordination number of 6. The hybridization involved is \( sp^3d^2 \).
- **Square Planar Geometry**: Requires a coordination number of 4. The hybridization involved is \( dsp^2 \).
- **Tetrahedral Geometry**: Requires a coordination number of 4. The hybridization involved is \( sp^3 \).
- **Trigonal Bipyramidal Geometry**: Requires a coordination number of 5. The hybridization involved is \( sp^3d \).

### Step 2: Analyze Each Option
1. **Option A**: Check if the complexes have octahedral geometry.
- Coordination number is 6.
- This option is correct.

2. **Option B**: Check if the complexes have square planar geometry.
- Coordination number is 4.
- This option is also correct.

3. **Option C**: Check if the complexes have tetrahedral geometry.
- Coordination number is 4.
- This option is correct as well.

4. **Option D**: Check if the complexes have trigonal bipyramidal geometry.
- Coordination number is stated as 6, which indicates octahedral geometry, not trigonal bipyramidal.
- This option is incorrect.

### Conclusion
The incorrect relationship between the coordination compound and its geometry is found in **Option D**.

### Final Answer
**Option D** is the incorrect set of examples and geometry of the compounds.

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