The reaction `CH_(2)=CH-CH_(3)+HBr rarr CH_(3)-overset(Br)overset(|)(C )HCH_(3)` is

Options

A. nucleophilic addition
B. free radical addition
C. electrophilic addition
D. electrophilic substitution

Explanation

To analyze the reaction \( CH_2=CH-CH_3 + HBr \rightarrow CH_3-CH(Br)-CH_3 \) and determine the type of reaction it represents, we will go through the following steps:

### Step 1: Identify the Reactants and Products
The reactant is propene (\( CH_2=CH-CH_3 \)), which is an alkene, and the product is 2-bromopropane (\( CH_3-CH(Br)-CH_3 \)).

**Hint:** Look for the functional groups and the type of compounds involved in the reaction.

### Step 2: Understand the Reaction Mechanism
In the presence of HBr, the double bond in propene can react. The hydrogen (H) from HBr will add to one of the carbon atoms involved in the double bond, while the bromine (Br) will add to the other carbon atom.

**Hint:** Identify how the double bond breaks and how the atoms from HBr are added to the alkene.

### Step 3: Determine the Role of HBr
HBr can be viewed as having a partial positive charge on hydrogen (acting as an electrophile) and a partial negative charge on bromine (acting as a nucleophile). In this reaction, the hydrogen atom will add to the carbon atom with fewer alkyl substituents (Markovnikov's rule), while the bromine will attach to the more substituted carbon.

**Hint:** Consider Markovnikov's rule when determining how HBr adds to the alkene.

### Step 4: Identify the Type of Reaction
Since the reaction involves the addition of HBr across the double bond of the alkene, it is classified as an electrophilic addition reaction. The double bond acts as a nucleophile, attacking the electrophilic hydrogen, leading to the formation of a carbocation intermediate. The bromide ion then attacks this carbocation.

**Hint:** Recall the definitions of nucleophilic addition, electrophilic addition, and substitution reactions to classify the reaction correctly.

### Step 5: Conclusion
The reaction \( CH_2=CH-CH_3 + HBr \rightarrow CH_3-CH(Br)-CH_3 \) is an **electrophilic addition reaction** because it involves the addition of an electrophile (H) to the alkene.

**Final Answer:** Electrophilic addition reaction.