Methyl bromide reacts with AgF to give methyl fluoride and silver bromide. This reaction is called

Options

A. Fitting reaction
B. Swart reaction
C. Wurtz reaction
D. Finkelstein reaction

Explanation

To solve the question regarding the reaction of methyl bromide with AgF to yield methyl fluoride and silver bromide, we will analyze the reaction step by step.

### Step-by-Step Solution:

1. **Identify the Reaction**: The reaction involves methyl bromide (CH3Br) reacting with silver fluoride (AgF) to produce methyl fluoride (CH3F) and silver bromide (AgBr). The balanced chemical equation for this reaction is:
\[ \text{CH}_3\text{Br} + \text{AgF} \rightarrow \text{CH}_3\text{F} + \text{AgBr} \]

2. **Classify the Reaction**: This type of reaction is characterized by the exchange of halogens. In this case, bromine from methyl bromide is replaced by fluorine from silver fluoride.

3. **Determine the Type of Reaction**: The reaction can be classified as a halogen exchange reaction, which is commonly known as a **Schwartz reaction**. This reaction is specifically used for the conversion of alkyl bromides to alkyl fluorides using silver fluoride.

4. **Eliminate Other Options**:
- **Wittig Reaction**: This involves the formation of alkenes from aldehydes or ketones and phosphonium ylides, which is not applicable here.
- **Wurtz Reaction**: This involves the coupling of alkyl halides in the presence of sodium to form alkanes, which does not describe the given reaction.
- **Finkelstein Reaction**: This involves the exchange of halogens, typically between iodides and other halides, but it specifically involves sodium iodide, not silver fluoride.

5. **Conclusion**: Based on the analysis, the reaction of methyl bromide with silver fluoride to produce methyl fluoride and silver bromide is classified as a **Schwartz reaction**.

### Final Answer:
The reaction is called the **Schwartz reaction**.