Identify the products (A) and (B) in the reactions.
`RX+AgCNtoul((A))+AgX`
`RX+KCNtoul((A))+KX`

Options

A. (A)-RCN, (B)- RCN
B. (A)-RCN, (B)-RNC
C. (A)-RNC, (B)-RCN
D. (A)-RNC, (B)-RNC

Explanation

To identify the products (A) and (B) in the given reactions, we need to analyze the reactions step by step.

### Step 1: Analyze the first reaction
The first reaction is:
\[ RX + AgCN \rightarrow (A) + AgX \]

- Here, \( RX \) represents an alkyl halide where \( R \) is an alkyl group and \( X \) is a halogen (Cl, Br, or I).
- When \( RX \) reacts with silver cyanide (\( AgCN \)), it forms a product (A) and a precipitate of silver halide (\( AgX \)).
- The product formed when an alkyl halide reacts with \( AgCN \) is isocyanide (\( RNC \)).

### Step 2: Analyze the second reaction
The second reaction is:
\[ RX + KCN \rightarrow (A) + KX \]

- In this case, \( KCN \) is potassium cyanide, which is ionic.
- When \( RX \) reacts with \( KCN \), it forms a product (A) and potassium halide (\( KX \)).
- The product formed when an alkyl halide reacts with \( KCN \) is alkyl cyanide (\( RCN \)).

### Conclusion
From the analysis:
- In the first reaction, product (A) is isocyanide (\( RNC \)).
- In the second reaction, product (A) is alkyl cyanide (\( RCN \)).
- The precipitate (B) in both reactions is the corresponding silver or potassium halide (\( AgX \) or \( KX \)).

Thus, the products are:
- (A) = \( RNC \) (isocyanide) from the first reaction.
- (B) = \( RCN \) (alkyl cyanide) from the second reaction.

### Final Answer
- Product (A) = Isocyanide (\( RNC \))
- Product (B) = Alkyl Cyanide (\( RCN \))