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Which of the following is the most react...

Which of the following is the most reactive towards nucleophilic substitution reaction?

A

`ClCH_2-CH=CH_2`

B

`CH_2=CH-Cl`

C

`CH_3CH=CH-Cl`

D

`C_6H_5Cl`

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The correct Answer is:
To determine which of the given reactants is most reactive towards nucleophilic substitution reactions, we need to analyze the stability of the carbocations formed during the reaction. Here's a step-by-step solution: ### Step 1: Identify the Reactants The reactants given are: 1. ClCH2-CH=CH2 (Allylic halide) 2. CH2=CH-CN (Vinylic halide) 3. CH3-CH=CH-CN (Allylic halide) 4. Chlorobenzene (C6H5Cl) ### Step 2: Understand Nucleophilic Substitution Nucleophilic substitution reactions involve the attack of a nucleophile on a carbon atom that is bonded to a leaving group (in this case, a halogen). The stability of the carbocation intermediate formed during this process is crucial for determining the reactivity of the compound. ### Step 3: Analyze the Reactants - **First Reactant (Allylic Halide)**: ClCH2-CH=CH2 - When this compound undergoes nucleophilic substitution, it forms an allylic carbocation (CH2=CH-CH2+). Allylic carbocations are relatively stable due to resonance stabilization. - **Second Reactant (Vinylic Halide)**: CH2=CH-CN - This compound forms a vinylic carbocation (CH2=C+-CN) upon nucleophilic attack. Vinylic carbocations are generally less stable than allylic carbocations due to the lack of resonance stabilization. - **Third Reactant (Allylic Halide)**: CH3-CH=CH-CN - Similar to the first reactant, this also forms an allylic carbocation (CH2=CH-CH3+), which is stable due to resonance. - **Fourth Reactant (Chlorobenzene)**: C6H5Cl - Chlorobenzene does not readily undergo nucleophilic substitution due to the stability of the aromatic ring and the lack of a suitable carbocation formation. ### Step 4: Compare the Stability of Carbocations - Allylic carbocations (from the first and third reactants) are more stable than vinylic carbocations (from the second reactant). - Among the allylic carbocations, the one from the first reactant (ClCH2-CH=CH2) is more stable due to the presence of the chlorine atom, which can stabilize the positive charge through inductive effects. ### Step 5: Conclusion Based on the stability of the carbocations formed, the most reactive compound towards nucleophilic substitution is the first reactant: **ClCH2-CH=CH2**. ### Final Answer **The most reactive towards nucleophilic substitution reaction is ClCH2-CH=CH2 (the first reactant).**

To determine which of the given reactants is most reactive towards nucleophilic substitution reactions, we need to analyze the stability of the carbocations formed during the reaction. Here's a step-by-step solution: ### Step 1: Identify the Reactants The reactants given are: 1. ClCH2-CH=CH2 (Allylic halide) 2. CH2=CH-CN (Vinylic halide) 3. CH3-CH=CH-CN (Allylic halide) 4. Chlorobenzene (C6H5Cl) ...
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