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Identify the products X and Y in the giv...

Identify the products X and Y in the given reaction,
`CH_3-underset(Br)underset(|)CH-CH_3+Mgoverset("Dry ether")rarrXoverset(D_2O)rarrY`

A

`X=CH_3-underset(Br)underset(|)CH-CH_2Mg,Y=CH_3CH_2CH_2OH`

B

`X=CH_3-underset(MgBr)underset(|)CH-CH_3,Y=CH_3,Y=CH_3-underset(D)underset(|)CH-CH_3`

C

`X=CH_3-underset(Br)underset(|)CH-CH_2Mg,Y=CH_3-underset(OD)underset(|)CH-CH_3`

D

`X=CH_3-underset(Br)underset(|)CH-CH_2Mg, Y=CH_3-underset(OH)underset(|)CH-CH_3`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to identify the products X and Y from the given reaction involving an alkyl halide, magnesium, and deuterated water (D2O). ### Step-by-Step Solution: 1. **Identify the Alkyl Halide**: The alkyl halide given is CH3-CH(Br)-CH3, which is 2-bromopropane. **Hint**: Look for the structure of the alkyl halide and identify the carbon bonded to the halogen. 2. **Formation of Grignard Reagent**: When 2-bromopropane reacts with magnesium (Mg) in dry ether, it forms a Grignard reagent. The reaction can be represented as: \[ \text{CH}_3\text{CH(Br)CH}_3 + \text{Mg} \xrightarrow{\text{Dry Ether}} \text{CH}_3\text{CH(MgBr)CH}_3 \] The product X is therefore CH3-CH(MgBr)-CH3. **Hint**: Remember that Grignard reagents are formed by the reaction of alkyl halides with magnesium in an anhydrous environment. 3. **Hydrolysis of Grignard Reagent**: The Grignard reagent (X) is then treated with deuterated water (D2O). The hydrolysis of Grignard reagents typically results in the formation of an alkane and a magnesium salt. In this case, instead of hydrogen (H), deuterium (D) will be incorporated into the product. The reaction can be represented as: \[ \text{CH}_3\text{CH(MgBr)CH}_3 + \text{D}_2\text{O} \rightarrow \text{CH}_3\text{CH(D)CH}_3 + \text{MgBrOD} \] Thus, the product Y is CH3-CH(D)-CH3, which is 2-deuteropropane. **Hint**: When hydrolyzing Grignard reagents, remember that the halogen is replaced by a hydrogen or, in this case, deuterium. ### Final Products: - **Product X**: CH3-CH(MgBr)-CH3 (Grignard reagent) - **Product Y**: CH3-CH(D)-CH3 (2-deuteropropane) ### Summary: - X is CH3-CH(MgBr)-CH3 - Y is CH3-CH(D)-CH3

To solve the problem, we need to identify the products X and Y from the given reaction involving an alkyl halide, magnesium, and deuterated water (D2O). ### Step-by-Step Solution: 1. **Identify the Alkyl Halide**: The alkyl halide given is CH3-CH(Br)-CH3, which is 2-bromopropane. **Hint**: Look for the structure of the alkyl halide and identify the carbon bonded to the halogen. ...
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Knowledge Check

  • The IUPAC name of CH_3 -underset(CH_3)underset(|)CH-CH_2 - overset(O)overset(||)C-Br is

    A
    2-Methylbutanoyl bromide
    B
    2-Methylbutan-4-oyl bromide
    C
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    D
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    A
    `CH_3-underset(H)underset(|)overset(CH_3)overset(|)C-CH_2OCH_3`
    B
    `CH_3-underset(OCH_3)underset(|)(CH)-CH_2CH_3`
    C
    `CH_3-overset(CH_3)overset(|)C=CH_2`
    D
    `CH_3-underset(OCH_3)underset(|)overset(CH_3)overset(|)C-CH_3`
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