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In two separate experiments equal quanti...

In two separate experiments equal quantities of alkyl halide, `C_4H_9Cl`, were treated at the same temperature with equal volume of 0.1 molar and 0.2 molar solutions of NaOH respectively. In the two experiments, `t_(1//2)` of the two reaction were the same. The most likely structure of halide is

A

`CH_3CH_2CH_2CH_2Cl`

B

`CH_3CH(Cl)CH_2CH_3`

C

`(CH_3)_2CHCH_2Cl`

D

`(CH_3)_3C Cl`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the information given about the reactions of the alkyl halide \( C_4H_9Cl \) with sodium hydroxide (NaOH) in two separate experiments. ### Step 1: Understand the Reaction Conditions We have two experiments where equal quantities of \( C_4H_9Cl \) are treated with two different concentrations of NaOH (0.1 M and 0.2 M). Both reactions are conducted at the same temperature and with equal volumes of the NaOH solution. **Hint:** Pay attention to how concentration affects reaction rates in different types of nucleophilic substitution reactions (SN1 vs. SN2). ### Step 2: Analyze the Half-Life (t1/2) The problem states that the half-life (\( t_{1/2} \)) of the reactions in both experiments is the same. In nucleophilic substitution reactions, the half-life can provide insight into the mechanism of the reaction: - For **SN1 reactions**, the half-life is independent of the concentration of the nucleophile. - For **SN2 reactions**, the half-life is dependent on the concentration of both the substrate and the nucleophile. **Hint:** Since the half-lives are the same despite different concentrations of NaOH, this suggests that the reaction follows an SN1 mechanism. ### Step 3: Determine the Structure of the Alkyl Halide SN1 reactions are favored by tertiary (3°) alkyl halides because they can form stable carbocations. The order of stability for carbocations is: - Tertiary (3°) > Secondary (2°) > Primary (1°) Since the reaction is likely SN1, we can conclude that the structure of \( C_4H_9Cl \) is most likely a tertiary alkyl halide. **Hint:** Look for the option that represents a tertiary alkyl halide among the choices provided. ### Step 4: Identify the Correct Structure Among the possible structures for \( C_4H_9Cl \), the one that is a tertiary alkyl halide is the most likely candidate. **Hint:** Check the given options for a structure that has the chlorine atom attached to a carbon that is connected to three other carbons. ### Conclusion Based on the analysis, the most likely structure of the halide \( C_4H_9Cl \) is a tertiary alkyl halide. ### Final Answer The most likely structure of the halide is a tertiary alkyl halide.

To solve the problem, we need to analyze the information given about the reactions of the alkyl halide \( C_4H_9Cl \) with sodium hydroxide (NaOH) in two separate experiments. ### Step 1: Understand the Reaction Conditions We have two experiments where equal quantities of \( C_4H_9Cl \) are treated with two different concentrations of NaOH (0.1 M and 0.2 M). Both reactions are conducted at the same temperature and with equal volumes of the NaOH solution. **Hint:** Pay attention to how concentration affects reaction rates in different types of nucleophilic substitution reactions (SN1 vs. SN2). ### Step 2: Analyze the Half-Life (t1/2) ...
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