The position of Br in the compound in `CH_(2)=CHC(Br)(CH_(3))_(2)` can be classified as……..

Options

A. allyl
B. aryl
C. vinyl
D. secondary

Answer

To classify the position of Br in the compound `CH₂=CHC(Br)(CH₃)₂`, we will analyze the structure and identify the type of carbon atom to which the bromine (Br) is attached.

### Step-by-Step Solution:

1. **Identify the Structure of the Compound**:
The compound `CH₂=CHC(Br)(CH₃)₂` can be represented as follows:
- The first part `CH₂=CH` indicates a double bond between the first two carbon atoms.
- The `C(Br)(CH₃)₂` part indicates that there is a carbon atom (the third carbon) that is bonded to a bromine atom (Br) and two methyl groups (CH₃).

2. **Draw the Structure**:
The structure can be drawn as:
```
CH2
|
CH
|
C(Br)(CH3)2
```
Here, the carbon atom that is bonded to Br is connected to the double bond and also to two methyl groups.

3. **Determine the Type of Carbon**:
- The carbon atom to which Br is attached is bonded to two other carbon atoms (one from the double bond and one from the methyl group).
- This carbon is therefore a **secondary carbon** because it is attached to two other carbon atoms.

4. **Classify the Position of Br**:
- Since the bromine is attached to a secondary carbon, we classify the position of Br as a **secondary halide**.

### Final Answer:
The position of Br in the compound `CH₂=CHC(Br)(CH₃)₂` can be classified as a **secondary halide**.

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