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Assertion: S(N^1) reactions are generall...

Assertion: `S_(N^1)` reactions are generally carried out in polar protic solvents (like water,alcohol, acetic acid etc.)
Reason: `C_6H_5CH(C_6H_5)Br` is less reactive than `C_6H_5CH(CH_3)Br` in `S_(N^1)` reactions.

A

If both assertion and reason are true and reason Is the correct explanation of assertion.

B

If both assertion and reason are true but reason is not the correct explanation of assertion.

C

If assetion is true but reason is false.

D

If both assertion and reason are false.

Text Solution

AI Generated Solution

The correct Answer is:
To analyze the assertion and reason provided in the question, we will break down the concepts involved in \( S_N1 \) reactions and the reactivity of the given compounds. ### Step 1: Understanding \( S_N1 \) Reactions - **Assertion**: \( S_N1 \) reactions are generally carried out in polar protic solvents. - **Explanation**: \( S_N1 \) reactions involve the formation of a carbocation intermediate. Polar protic solvents stabilize this carbocation by solvation, which is crucial for the reaction to proceed. Therefore, the assertion is true. ### Step 2: Comparing Reactivity of the Two Compounds - **Reason**: We need to compare the reactivity of \( C_6H_5CH(C_6H_5)Br \) (let's call it Compound A) and \( C_6H_5CH(CH_3)Br \) (let's call it Compound B) in \( S_N1 \) reactions. - **Analysis**: - Compound A has two phenyl groups attached to the carbon bearing the leaving group (bromine), which can stabilize the carbocation formed after the leaving group departs. - Compound B has only one phenyl group attached to the same carbon. The presence of the methyl group (CH₃) does not provide as much stabilization as the second phenyl group. ### Step 3: Stability of Carbocations - **Carbocation Stability**: The stability of a carbocation increases with the number of alkyl or aryl groups attached to the positively charged carbon. - **Conclusion**: The carbocation formed from Compound A is more stable than that from Compound B due to the presence of two phenyl groups, making Compound A more reactive in \( S_N1 \) reactions than Compound B. ### Final Evaluation - **Assertion**: True (because \( S_N1 \) reactions are indeed carried out in polar protic solvents). - **Reason**: False (because Compound A is more reactive than Compound B, not less). ### Answer The assertion is true, but the reason is false.

To analyze the assertion and reason provided in the question, we will break down the concepts involved in \( S_N1 \) reactions and the reactivity of the given compounds. ### Step 1: Understanding \( S_N1 \) Reactions - **Assertion**: \( S_N1 \) reactions are generally carried out in polar protic solvents. - **Explanation**: \( S_N1 \) reactions involve the formation of a carbocation intermediate. Polar protic solvents stabilize this carbocation by solvation, which is crucial for the reaction to proceed. Therefore, the assertion is true. ### Step 2: Comparing Reactivity of the Two Compounds - **Reason**: We need to compare the reactivity of \( C_6H_5CH(C_6H_5)Br \) (let's call it Compound A) and \( C_6H_5CH(CH_3)Br \) (let's call it Compound B) in \( S_N1 \) reactions. ...
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