A compound `C_(6)H_(14)O_(2)` has two tertiary alcoholic groups . The IUPAC name of this compound is

Options

A. 2,3-dimethyl -1, 2 - butanediol
B. 3,3-dimethyl - 1 , 2 - butanediol
C. 2,3-dimethyl-2 , 3-butanediol
D. 2-methyl-2 , 3- pentanediol .

Explanation

To determine the IUPAC name of the compound with the formula \( C_6H_{14}O_2 \) that contains two tertiary alcoholic groups, we can follow these steps:

### Step 1: Understand the Structure
We know that a tertiary alcohol is one where the carbon atom bearing the hydroxyl group (–OH) is attached to three other carbon atoms. Given that the compound has the formula \( C_6H_{14}O_2 \), we can infer that it has two hydroxyl groups.

### Step 2: Determine the Carbon Skeleton
Since the compound has six carbon atoms, we can start with a six-carbon chain. The base structure will be hexane (C6).

### Step 3: Position the Hydroxyl Groups
To have two tertiary alcohols, we need to place the hydroxyl groups on carbon atoms that are each connected to three other carbon atoms. The only way to achieve this in a six-carbon chain is to place the hydroxyl groups on the second and third carbon atoms.

### Step 4: Identify the Substituents
Next, we need to check for any substituents. In this case, we can add methyl groups to the carbon chain to ensure that the carbons with the hydroxyl groups are tertiary.

### Step 5: Draw the Structure
The structure can be represented as follows:
- The main chain is hexane.
- The hydroxyl groups are on the second and third carbons.
- Methyl groups can be added to the second and third carbons to ensure they are tertiary.

### Step 6: Naming the Compound
The compound will be named based on the positions of the hydroxyl groups and any substituents. The correct IUPAC name for this compound is **2,3-dimethyl-2,3-hexanediol**.

### Final Answer
The IUPAC name of the compound \( C_6H_{14}O_2 \) with two tertiary alcoholic groups is **2,3-dimethyl-2,3-hexanediol**.

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