1-Phenylethanol can be prepared by the reaction of benzaldehyde with the product obtained in the reaction between :

Options

A. methyl bromide
B. ethyl iodide and magnesium
C. methyl iodide and magnesium
D. methyl bromide and aluminium bromide .

Explanation

To solve the question of how to prepare 1-phenylethanol from benzaldehyde, we need to analyze the reactions involved with the given options.

### Step-by-Step Solution:

1. **Understanding the Target Compound**:
- We need to prepare 1-phenylethanol, which has the structure:
\[ \text{C}_6\text{H}_5\text{CH(OH)CH}_3 \]
- This compound can be formed by adding a methyl group (from a methyl halide) to benzaldehyde.

2. **Identifying the Reaction Type**:
- The reaction we are looking for is a nucleophilic addition reaction. We will need a Grignard reagent (which is formed from a methyl halide and magnesium) to act as the nucleophile.

3. **Analyzing the Options**:
- **Option 1: Methyl Bromide**:
- Methyl bromide alone cannot form a Grignard reagent without magnesium, so this option is not viable.
- **Option 2: Methyl Iodide and Magnesium**:
- This combination can form a Grignard reagent (CH₃MgI). The Grignard reagent can then react with benzaldehyde.
- **Option 3: Methyl Iodide and Magnesium**:
- This is the same as option 2, which again forms CH₃MgI and can react with benzaldehyde.
- **Option 4: Methyl Bromide and Aluminum Bromide**:
- Methyl bromide with aluminum bromide does not form a Grignard reagent and thus cannot react with benzaldehyde.

4. **Determining the Correct Option**:
- Both options 2 and 3 lead to the formation of CH₃MgI, which can react with benzaldehyde to produce 1-phenylethanol. However, since the question asks for the reaction between benzaldehyde and the product obtained, we can conclude that the correct answer is either option 2 or option 3.

5. **Final Conclusion**:
- The correct answer is **Methyl Iodide and Magnesium** (either option 2 or option 3).