What would be the reactant and reagent used to obtain 2,4 - dimethylpentan-3-ol ?

Options

A. Propanal and proyl magnesium bromide
B. 3-Methybutanal and 2- methyl magnesium iodide
C. 2,2-Dimethylpropanone and methyl magnesium iodide
D. 2- Methylpropanal and isopropyl magnesium iodide

Explanation

To obtain 2,4-dimethylpentan-3-ol, we need to identify the appropriate reactants and reagents. Here’s a step-by-step breakdown of the solution:

### Step 1: Identify the target compound
The target compound is 2,4-dimethylpentan-3-ol. This compound has the following structure:
- It is a pentane derivative (5 carbon atoms in the main chain).
- It has two methyl groups at the 2nd and 4th positions.
- It has a hydroxyl (-OH) group at the 3rd position.

### Step 2: Determine the reactants
To synthesize 2,4-dimethylpentan-3-ol, we can start with a suitable ketone or aldehyde and an alcohol.

A good choice for the carbon skeleton would be a ketone that can provide the necessary carbon chain. In this case, we can use 2-pentanone as the starting ketone.

### Step 3: Identify the reagent
To convert the ketone into the desired alcohol, we can use a Grignard reagent. A suitable Grignard reagent for this synthesis is isopropyl magnesium iodide (which can be derived from isopropyl bromide and magnesium).

### Step 4: Write the reaction
The reaction can be summarized as follows:
1. Start with 2-pentanone (the ketone).
2. React it with isopropyl magnesium iodide (the Grignard reagent).
3. Finally, add water (H2O) to quench the reaction and form the alcohol.

### Final Reaction Equation
The overall reaction can be represented as:
\[ \text{2-pentanone} + \text{isopropyl magnesium iodide} \xrightarrow{\text{H2O}} \text{2,4-dimethylpentan-3-ol} \]

### Conclusion
Thus, the reactants and reagents needed to obtain 2,4-dimethylpentan-3-ol are:
- **Reactants**: 2-pentanone
- **Reagent**: Isopropyl magnesium iodide