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In reaction C(2)H(5)OH+Hxoverset(ZnX(2))...

In reaction `C_(2)H_(5)OH+Hxoverset(ZnX_(2))rarrC_(2)H_(5)X+H_(2)O` the order of reactivity of HX is :

A

`HCl gt HBr gt HI`

B

`HI gt HBr gt HCl`

C

`HBr gt HCl gt HI`

D

`HI gt HCl gt HBr`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the order of reactivity of HX in the reaction \( C_2H_5OH + HX \overset{ZnX_2}{\rightarrow} C_2H_5X + H_2O \), we need to analyze the nucleophilicity of the halide ions involved (I^-, Br^-, Cl^-). ### Step-by-Step Solution: 1. **Identify the Reactants and Products**: - The reactants are ethanol (\( C_2H_5OH \)) and a hydrogen halide (\( HX \)). - The products are an alkyl halide (\( C_2H_5X \)) and water (\( H_2O \)). 2. **Understand the Role of HX**: - In this reaction, \( HX \) provides the halide ion \( X^- \) which acts as a nucleophile. - The strength of the nucleophile will influence the reactivity of the reaction. 3. **Consider Nucleophilicity**: - Nucleophilicity is the ability of a species to donate a pair of electrons to an electrophile. - It is inversely related to the electronegativity of the atom carrying the negative charge. 4. **Order of Electronegativity**: - The electronegativity of halogens decreases in the order: \( F > Cl > Br > I \). - Therefore, the order of nucleophilicity for the halide ions (in terms of their ability to act as nucleophiles) is: - I^- > Br^- > Cl^-. 5. **Determine the Order of Reactivity**: - Since I^- is the most nucleophilic and Cl^- is the least, the order of reactivity of the hydrogen halides (HX) based on their nucleophilicity is: - HI > HBr > HCl. 6. **Select the Correct Option**: - From the options provided: 1. HCl > HBr > HI 2. HI > HBr > HCl (this is correct) 3. HBr > HCl > HI 4. HI > HCl > HBr - The correct order of reactivity is given in option 2: HI > HBr > HCl. ### Final Answer: The order of reactivity of HX is: **HI > HBr > HCl** (Option 2).
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