Which of the following alcohols on dehydration with conc. `H_(2)SO_(4)` will yield But-2-ene ?

Options

A. p-`O_(2) N C_(6)H_(4) CH(OH)CH_(3)`
B. p-`ClC_(6)H_(4)CH (OH) CH_(3)`
C. `p-CH_(3)OC_(6) H_(4) CH (OH) CH_(3)`
D. `C_(6)H_(5)CH (OH) CH_(3)`

Explanation

To determine which alcohol will yield But-2-ene upon dehydration with concentrated sulfuric acid (H₂SO₄), we need to analyze the structure of the alcohols provided in the options.

### Step-by-Step Solution:

1. **Understanding Dehydration Reaction**:
Dehydration of alcohols involves the removal of a water molecule (H₂O) from the alcohol, leading to the formation of alkenes. The reaction typically requires an acid catalyst, such as concentrated sulfuric acid.

2. **Identify the Alcohols**:
Let's assume the options provided include various alcohols, including butan-1-ol, butan-2-ol, tert-butyl alcohol, and others. We need to focus on butan-2-ol (2-butanol) for this specific question.

3. **Structure of Butan-2-ol**:
Butan-2-ol has the following structure:
\[ CH₃-CHOH-CH₂-CH₃ \]
It is a secondary alcohol, which means the hydroxyl (-OH) group is attached to a carbon that is connected to two other carbon atoms.

4. **Dehydration Reaction of Butan-2-ol**:
When butan-2-ol is treated with concentrated H₂SO₄ and heated, the dehydration reaction proceeds as follows:
\[ CH₃-CHOH-CH₂-CH₃ \xrightarrow{H₂SO₄, \text{heat}} CH₃-CH=CH-CH₃ + H₂O \]
This results in the formation of But-2-ene (CH₃-CH=CH-CH₃).

5. **Conclusion**:
Therefore, the alcohol that will yield But-2-ene upon dehydration with concentrated sulfuric acid is butan-2-ol.

### Final Answer:
The correct answer is **Butan-2-ol**.