A compound X with moleuclar formula `C_(3)H_(8)O` can be oxidized to a compoud Y with the molecular formula `C_(3)H_(6)O_(2)`. X is most likely to be a:

Options

A. `CH_(3)CH_(2)OCH_(3)`
B. `CH_(3)CH_(2)CHO`
C. `CH_(3)CH_(2)CH_(2)OH`
D. `CH_(3)CHOHCH_(3)`

Explanation

To determine the compound X with the molecular formula \( C_3H_8O \) that can be oxidized to compound Y with the molecular formula \( C_3H_6O_2 \), we can follow these steps:

### Step 1: Analyze the Molecular Formulas
- The molecular formula of compound X is \( C_3H_8O \).
- The molecular formula of compound Y is \( C_3H_6O_2 \).
- The oxidation process involves the loss of hydrogen and/or the addition of oxygen.

### Step 2: Determine Possible Functional Groups
- Given the molecular formula \( C_3H_8O \), compound X could be an alcohol or an aldehyde. However, ethers cannot be oxidized, so they are not a possibility.
- Alcohols can be classified as primary, secondary, or tertiary.

### Step 3: Consider the Oxidation Products
- When a primary alcohol is oxidized, it can form an aldehyde and then further oxidize to a carboxylic acid.
- Secondary alcohols oxidize to ketones, which do not match the formula of compound Y.
- Tertiary alcohols do not oxidize.

### Step 4: Identify the Correct Structure of X
- Since compound Y is a carboxylic acid \( C_3H_6O_2 \), we need to consider that compound X must be a primary alcohol that can be oxidized to a carboxylic acid.
- The structure of a primary alcohol that fits the molecular formula \( C_3H_8O \) is \( CH_3CH_2CH_2OH \) (1-propanol).

### Step 5: Confirm the Oxidation Reaction
- The oxidation of 1-propanol (\( CH_3CH_2CH_2OH \)) would yield propanoic acid (\( CH_3CH_2COOH \)), which has the formula \( C_3H_6O_2 \).
- This confirms that the oxidation process is valid.

### Conclusion
- Therefore, compound X is most likely to be **1-propanol**.