In the following reaction sequence,
`CH_(3) - underset((X))underset(OH)underset(|)(C)H-CH_(3) overset([O])(to) Y overset(CH_(3)MgBr)underset(H^(+)// H_(2)O)(to) Z`
Z is

Options

A. butan-1-ol
B. butan-2-ol
C. 2-methylpropan-2-ol
D. 1,1 - dimethylethanol.

Explanation

To solve the problem, we need to analyze the given reaction sequence step by step:

1. **Identify the Starting Material (X)**:
The starting material is 2-propanol, which can be represented as:
\[ CH_3 - CH(OH) - CH_3 \]

2. **Perform Oxidation to Obtain Y**:
The next step involves the oxidation of 2-propanol. When 2-propanol is oxidized, it converts to acetone (a ketone). The reaction can be represented as:
\[ CH_3 - CH(OH) - CH_3 \xrightarrow{[O]} CH_3 - C(=O) - CH_3 \]
Thus, Y is acetone:
\[ Y = CH_3 - C(=O) - CH_3 \]

3. **Reaction of Acetone with Methyl Magnesium Bromide**:
The next step involves the reaction of acetone (Y) with methyl magnesium bromide (CH₃MgBr). In this reaction, the nucleophilic methyl group (CH₃⁻) attacks the electrophilic carbon of the carbonyl group in acetone. The reaction can be represented as:
\[ CH_3 - C(=O) - CH_3 + CH_3MgBr \rightarrow CH_3 - C(OH)(CH_3) - CH_3 \]
This intermediate will have a negatively charged oxygen atom (alkoxide).

4. **Protonation of the Alkoxide**:
The final step involves protonation of the alkoxide by adding water (H⁺/H₂O). This leads to the formation of the final product:
\[ CH_3 - C(OH)(CH_3) - CH_3 \xrightarrow{H^+/H_2O} CH_3 - C(OH)(CH_3) - CH_3 \]
The product formed is 2-methylpropan-2-ol, which can also be represented as:
\[ Z = (CH_3)_2C(OH)CH_3 \]

5. **Conclusion**:
Therefore, the final product Z is 2-methylpropan-2-ol.

### Final Answer:
Z is 2-methylpropan-2-ol.